anonymous
  • anonymous
Your starship, the Aimless Wanderer, lands on the mysterious planet Mongo. As chief scientist-engineer, you make the following measurements: a 2.50-kg stone thrown upward from the ground at 15.0 m/s returns to the ground in 6.00 s; the circumference of Mongo at the equator is 4.00×105 km; there is no appreciable atmosphere, and the planet's mass is 3.04*10^26 kg. If the Aimless Wanderer goes into a circular orbit 3.00×104 km above the surface of Mongo, how many hours will it take the ship to complete one orbit?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Mani_Jha
  • Mani_Jha
\[Time=Distance(2pir)/Speed(\sqrt{GM/r)}\] r=Radius of Planet+3X10^4
Mani_Jha
  • Mani_Jha
Clear?
anonymous
  • anonymous
first u got to find the velocity with which the man orbits the planet centripetal force is provided by the graviational force of attraction GmM/r^2 so mv^2/r=GmM/r^2 find expression for velocity next speed=distance/time so time=distance/speed i know speed wat abt the distance? man goes in a circular orbit hence the orbits radius is R perimeter=2*pi*R |dw:1333021692767:dw| note the diff btw R and r(radius of planet)

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