## S Group Title What is the inflection point of f(x)=x^2(x^2-4) ? 2 years ago 2 years ago

$f(x)=x^2(x^2-4)=x^4-4x^2$$f'(x)=4x^3-8x$$f''(x)=12x^2-8$$12x^2-8=0\implies x=\pm\sqrt{\frac{2}{3}}$