anonymous
  • anonymous
Ok, so i'm a little stuck on this=p i've tried help, but i don't have many resources, since my family members don't know. Here is the question: A climber goes up the lower part of a 50-foot climbing wall at a rate of 1.2 ft/min. The upper part of the wall is more difficult, and she climbs at 0.8 ft/min. She reaches the top of the wall in 51.5 min. How long did it take her to climb the lower part of the wall? At what height on the wall did her rate change? (Hint: Model each part of the climb with a linear equation, using x for the time and y for distance. Then solve the system of two linear eq
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
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anonymous
  • anonymous
y is the distance for the harder part of the wall 50-y is the distance for the easier part x is the time she does the harder part 51.5 - x is the time she does the easier part.
anonymous
  • anonymous
x = 29.5 minutes y = 23.6 feet to answer the question "how long did she do the lower part..", 51.5-29.5 = 22minutes.

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anonymous
  • anonymous
idk, it looks right. do you have the answer?

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