can someone help me find the derivative to this equation 2xsqrtx^2+1

- anonymous

can someone help me find the derivative to this equation 2xsqrtx^2+1

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- jamiebookeater

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- anonymous

\[2x \sqrt{x^2+1}\]

- anonymous

actually i got all to the end of the i just can figure out how to simlify the damn thing to match the books answer

- anonymous

lemme do that again ... i just realized i didn't take the square root..

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

|dw:1333008783149:dw|

- anonymous

4x^2/2sqrtx^2+1 +x^2+1 and i dont know how to simplify this to get 2(2x^2+1)/sqrtx^2+1

- anonymous

|dw:1333008899711:dw|

- anonymous

factor out the common factor of 2(x^2+1)^(-1/2)

- anonymous

|dw:1333009455298:dw|

- anonymous

sorry i dont know what you did this is where am at 2[x(2x)/2sqrtx^2+1+sqrt x^2+1

- anonymous

Plz see the attachment

##### 1 Attachment

- anonymous

Is the photo clear? If not, I can upload another one

- anonymous

i can't make out what you wrote for your derivative (@ goku3)

- anonymous

would mind uploading another pic @CoCoTsoi

- anonymous

##### 1 Attachment

- anonymous

I agree with @CoCoTsoi 's answer.

- anonymous

It is beauteeeful.

- anonymous

i get lost between step to and three

- anonymous

Chain rule

- anonymous

why is there two 2x on top

- anonymous

And product rule...
http://tutorial.math.lamar.edu/Classes/CalcI/ProductQuotientRule.aspx

- anonymous

one 2x is the original one. another is by diff the equation inside the sqrt

- anonymous

So say if you have f*g. If you use the product rule, then you'll do:
f'*g + f*g'.

- anonymous

sorry if you couldn't see the tick mark next to the f.

- anonymous

its cool how you get rid of the sqrt on top

- anonymous

Okay so going from the 3rd to the 4th line:
There's 2sqrt(x^2+1)
He want's to get it so it has the same denominator as the other term. The den of the other term is sqrt(x^2+1).
So with the left term, you have to multiply the numerator and denominator by sqrt(x^2+1).
Then you end up with (2sqrt(x^2+1)*sqrt(x^2+1))/sqrt(x^2+1)
= (2(x^2+1))/sqrt(x^2+1)

- anonymous

lol... wants not want's. I type too fast.

- anonymous

multiply numerator and denominator with sqrt(x^2+1)

- anonymous

thank you guys so much every time i tried to do it i forgot to add one of the 2x and messed my entire thing up

- anonymous

We all tend to get lost in the little steps, believe me I've been there. Coco did a great job writing that out.

- anonymous

Coz I was lazy for typing it on keyboard so I chose to write it on paper :D

- anonymous

paper is way faster and thank u guys for being so patient with me

- anonymous

So goku, remember with this problem, you have to use the product rule and then the chain rule since you have stuff inside of that square root.

- anonymous

Thanks for giving a chance for us to learn

- anonymous

yeah i will i just have to take my on these problems and not rush them

- anonymous

Check out paul's online notes if you haven't already, they are great :-)

- anonymous

i have them bookmarked actually

Looking for something else?

Not the answer you are looking for? Search for more explanations.