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goku3
 3 years ago
can someone help me find the derivative to this equation 2xsqrtx^2+1
goku3
 3 years ago
can someone help me find the derivative to this equation 2xsqrtx^2+1

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goku3
 3 years ago
Best ResponseYou've already chosen the best response.0actually i got all to the end of the i just can figure out how to simlify the damn thing to match the books answer

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.4lemme do that again ... i just realized i didn't take the square root..

goku3
 3 years ago
Best ResponseYou've already chosen the best response.04x^2/2sqrtx^2+1 +x^2+1 and i dont know how to simplify this to get 2(2x^2+1)/sqrtx^2+1

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.4factor out the common factor of 2(x^2+1)^(1/2)

goku3
 3 years ago
Best ResponseYou've already chosen the best response.0sorry i dont know what you did this is where am at 2[x(2x)/2sqrtx^2+1+sqrt x^2+1

CoCoTsoi
 3 years ago
Best ResponseYou've already chosen the best response.1Plz see the attachment

CoCoTsoi
 3 years ago
Best ResponseYou've already chosen the best response.1Is the photo clear? If not, I can upload another one

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.4i can't make out what you wrote for your derivative (@ goku3)

goku3
 3 years ago
Best ResponseYou've already chosen the best response.0would mind uploading another pic @CoCoTsoi

brinethery
 3 years ago
Best ResponseYou've already chosen the best response.1I agree with @CoCoTsoi 's answer.

goku3
 3 years ago
Best ResponseYou've already chosen the best response.0i get lost between step to and three

goku3
 3 years ago
Best ResponseYou've already chosen the best response.0why is there two 2x on top

brinethery
 3 years ago
Best ResponseYou've already chosen the best response.1And product rule... http://tutorial.math.lamar.edu/Classes/CalcI/ProductQuotientRule.aspx

CoCoTsoi
 3 years ago
Best ResponseYou've already chosen the best response.1one 2x is the original one. another is by diff the equation inside the sqrt

brinethery
 3 years ago
Best ResponseYou've already chosen the best response.1So say if you have f*g. If you use the product rule, then you'll do: f'*g + f*g'.

brinethery
 3 years ago
Best ResponseYou've already chosen the best response.1sorry if you couldn't see the tick mark next to the f.

goku3
 3 years ago
Best ResponseYou've already chosen the best response.0its cool how you get rid of the sqrt on top

brinethery
 3 years ago
Best ResponseYou've already chosen the best response.1Okay so going from the 3rd to the 4th line: There's 2sqrt(x^2+1) He want's to get it so it has the same denominator as the other term. The den of the other term is sqrt(x^2+1). So with the left term, you have to multiply the numerator and denominator by sqrt(x^2+1). Then you end up with (2sqrt(x^2+1)*sqrt(x^2+1))/sqrt(x^2+1) = (2(x^2+1))/sqrt(x^2+1)

brinethery
 3 years ago
Best ResponseYou've already chosen the best response.1lol... wants not want's. I type too fast.

CoCoTsoi
 3 years ago
Best ResponseYou've already chosen the best response.1multiply numerator and denominator with sqrt(x^2+1)

goku3
 3 years ago
Best ResponseYou've already chosen the best response.0thank you guys so much every time i tried to do it i forgot to add one of the 2x and messed my entire thing up

brinethery
 3 years ago
Best ResponseYou've already chosen the best response.1We all tend to get lost in the little steps, believe me I've been there. Coco did a great job writing that out.

CoCoTsoi
 3 years ago
Best ResponseYou've already chosen the best response.1Coz I was lazy for typing it on keyboard so I chose to write it on paper :D

goku3
 3 years ago
Best ResponseYou've already chosen the best response.0paper is way faster and thank u guys for being so patient with me

brinethery
 3 years ago
Best ResponseYou've already chosen the best response.1So goku, remember with this problem, you have to use the product rule and then the chain rule since you have stuff inside of that square root.

CoCoTsoi
 3 years ago
Best ResponseYou've already chosen the best response.1Thanks for giving a chance for us to learn

goku3
 3 years ago
Best ResponseYou've already chosen the best response.0yeah i will i just have to take my on these problems and not rush them

brinethery
 3 years ago
Best ResponseYou've already chosen the best response.1Check out paul's online notes if you haven't already, they are great :)

goku3
 3 years ago
Best ResponseYou've already chosen the best response.0i have them bookmarked actually
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