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goku3Best ResponseYou've already chosen the best response.0
actually i got all to the end of the i just can figure out how to simlify the damn thing to match the books answer
 2 years ago

dpaIncBest ResponseYou've already chosen the best response.4
lemme do that again ... i just realized i didn't take the square root..
 2 years ago

goku3Best ResponseYou've already chosen the best response.0
4x^2/2sqrtx^2+1 +x^2+1 and i dont know how to simplify this to get 2(2x^2+1)/sqrtx^2+1
 2 years ago

dpaIncBest ResponseYou've already chosen the best response.4
factor out the common factor of 2(x^2+1)^(1/2)
 2 years ago

goku3Best ResponseYou've already chosen the best response.0
sorry i dont know what you did this is where am at 2[x(2x)/2sqrtx^2+1+sqrt x^2+1
 2 years ago

CoCoTsoiBest ResponseYou've already chosen the best response.1
Plz see the attachment
 2 years ago

CoCoTsoiBest ResponseYou've already chosen the best response.1
Is the photo clear? If not, I can upload another one
 2 years ago

dpaIncBest ResponseYou've already chosen the best response.4
i can't make out what you wrote for your derivative (@ goku3)
 2 years ago

goku3Best ResponseYou've already chosen the best response.0
would mind uploading another pic @CoCoTsoi
 2 years ago

brinetheryBest ResponseYou've already chosen the best response.1
I agree with @CoCoTsoi 's answer.
 2 years ago

goku3Best ResponseYou've already chosen the best response.0
i get lost between step to and three
 2 years ago

goku3Best ResponseYou've already chosen the best response.0
why is there two 2x on top
 2 years ago

brinetheryBest ResponseYou've already chosen the best response.1
And product rule... http://tutorial.math.lamar.edu/Classes/CalcI/ProductQuotientRule.aspx
 2 years ago

CoCoTsoiBest ResponseYou've already chosen the best response.1
one 2x is the original one. another is by diff the equation inside the sqrt
 2 years ago

brinetheryBest ResponseYou've already chosen the best response.1
So say if you have f*g. If you use the product rule, then you'll do: f'*g + f*g'.
 2 years ago

brinetheryBest ResponseYou've already chosen the best response.1
sorry if you couldn't see the tick mark next to the f.
 2 years ago

goku3Best ResponseYou've already chosen the best response.0
its cool how you get rid of the sqrt on top
 2 years ago

brinetheryBest ResponseYou've already chosen the best response.1
Okay so going from the 3rd to the 4th line: There's 2sqrt(x^2+1) He want's to get it so it has the same denominator as the other term. The den of the other term is sqrt(x^2+1). So with the left term, you have to multiply the numerator and denominator by sqrt(x^2+1). Then you end up with (2sqrt(x^2+1)*sqrt(x^2+1))/sqrt(x^2+1) = (2(x^2+1))/sqrt(x^2+1)
 2 years ago

brinetheryBest ResponseYou've already chosen the best response.1
lol... wants not want's. I type too fast.
 2 years ago

CoCoTsoiBest ResponseYou've already chosen the best response.1
multiply numerator and denominator with sqrt(x^2+1)
 2 years ago

goku3Best ResponseYou've already chosen the best response.0
thank you guys so much every time i tried to do it i forgot to add one of the 2x and messed my entire thing up
 2 years ago

brinetheryBest ResponseYou've already chosen the best response.1
We all tend to get lost in the little steps, believe me I've been there. Coco did a great job writing that out.
 2 years ago

CoCoTsoiBest ResponseYou've already chosen the best response.1
Coz I was lazy for typing it on keyboard so I chose to write it on paper :D
 2 years ago

goku3Best ResponseYou've already chosen the best response.0
paper is way faster and thank u guys for being so patient with me
 2 years ago

brinetheryBest ResponseYou've already chosen the best response.1
So goku, remember with this problem, you have to use the product rule and then the chain rule since you have stuff inside of that square root.
 2 years ago

CoCoTsoiBest ResponseYou've already chosen the best response.1
Thanks for giving a chance for us to learn
 2 years ago

goku3Best ResponseYou've already chosen the best response.0
yeah i will i just have to take my on these problems and not rush them
 2 years ago

brinetheryBest ResponseYou've already chosen the best response.1
Check out paul's online notes if you haven't already, they are great :)
 2 years ago

goku3Best ResponseYou've already chosen the best response.0
i have them bookmarked actually
 2 years ago
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