apoorvk
  • apoorvk
Three friends Roger, Djoko and Rafael (:p) went to watch a tournament of tennis on a certain day of the event, when a total of 7 matches were being held (no match-timings coinciding with any other). All the 3 friends can either watch a match or loiter around in the arena with the probability ratio (3:1) On entering the arena, all 3 went their separate ways. Find the probability of none of them having witnessed any particular match together.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
:( I can't solve it, @foolformath HELP.
apoorvk
  • apoorvk
nahii.. ISHAAN, ye naaahhiii ho saktaa!! :p :D
anonymous
  • anonymous
I can't also.

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More answers

anonymous
  • anonymous
lol @mr.math @dumbcow
apoorvk
  • apoorvk
@myininaya
apoorvk
  • apoorvk
help myininaya, please!!!
anonymous
  • anonymous
should be 1 in 448
anonymous
  • anonymous
How?
apoorvk
  • apoorvk
now explanation will be appreciated. :)
apoorvk
  • apoorvk
am getting stuck somewhere. and i can't untangle my mind.. :/
anonymous
  • anonymous
Change my answer. 27 in 448 chance that they will all meet, 136 in 448 chance that a and b will meet, 136 in 448 chance that b and c will meet, 136 in 448 chance that a and c will meet. 3*136- 2*27= 354 in 448 chance that they will meet at all. Therefore 94 in 448 (you can simplify it) chance that they will not meet at all.
anonymous
  • anonymous
Timings of the match doesn't coincide with eachother, so when they enter the stadium they must have only one match to watch, lets they don't watch it together. So, there must be three cases either one of them watches the match or two or none. \[\text{_________________________________________________________________________________}\]Now help me do the math.
lgbasallote
  • lgbasallote
no one's calling for lgbaaaa :( well i dunno this either...
Mani_Jha
  • Mani_Jha
For each of the three persons, there are two choices - watch the match or not, for each of the seven matches. So, total no of ways in which each one completes the day is 2X2X2..=2^7. Is this right so far?
Mani_Jha
  • Mani_Jha
The total no of choices for the 3 people would be 3X2^7. Atleast I found out the denominator of my fraction..:P
apoorvk
  • apoorvk
right so far mani, and i seem to be seeing it clearer now.
apoorvk
  • apoorvk
unhnn....the choices for the three would get multiplied rendering your denominator 2^21, since it is an 'OR' case, where each member may watch a match or not, and each person's choice being an independent event.
apoorvk
  • apoorvk
'OR'
Mani_Jha
  • Mani_Jha
oh yeah. you're right. Now let me think how to use the given probability ratio.
Mani_Jha
  • Mani_Jha
@ch2831, where did you get the number 448 from?
anonymous
  • anonymous
The names have been badly chosen :P
anonymous
  • anonymous
4*4*4*7. Isnt it 448?
Mani_Jha
  • Mani_Jha
Yeah, it is. Please explain why you chose that number. To be honest, I didn't understand your answer.
dumbcow
  • dumbcow
hmm i'm getting a really small probability here --> (5/32)^7 each match is an independent event so you would multiply the probabilities hence raising to 7th power each match has 4 possiblilties None watch: --> (1/4)^3 = 1/64 1 watches: --> 3*(3/4)*(1/4)^2 = 9/64 2 watches --> 3*(3/4)^2*(1/4) = 27/64 All watch --> (3/4)^3 = 27/64 so probability less than 2 watch any given match is 10/64 = 5/32
anonymous
  • anonymous
Oh so this is how the probability ratio is used
Mani_Jha
  • Mani_Jha
Oh...This topic really isn't made for me :=(
dumbcow
  • dumbcow
i believe that is right, the probability you watch is 3 times greater than not watching
apoorvk
  • apoorvk
@dumbcow .. yayy!!!!!!!!!! you did it i guess!!! yeah he took the ratio thing right too, ishaan!
apoorvk
  • apoorvk
@arcticf0x , the names have been *purposefully* chosen. :p
anonymous
  • anonymous
Nice solution :-) #I need to study probability :/

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