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 2 years ago
Three friends Roger, Djoko and Rafael (:p) went to watch a tournament of tennis on a certain day of the event, when a total of 7 matches were being held (no matchtimings coinciding with any other). All the 3 friends can either watch a match or loiter around in the arena with the probability ratio (3:1) On entering the arena, all 3 went their separate ways. Find the probability of none of them having witnessed any particular match together.
 2 years ago
Three friends Roger, Djoko and Rafael (:p) went to watch a tournament of tennis on a certain day of the event, when a total of 7 matches were being held (no matchtimings coinciding with any other). All the 3 friends can either watch a match or loiter around in the arena with the probability ratio (3:1) On entering the arena, all 3 went their separate ways. Find the probability of none of them having witnessed any particular match together.

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Ishaan94
 2 years ago
Best ResponseYou've already chosen the best response.0:( I can't solve it, @foolformath HELP.

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.1nahii.. ISHAAN, ye naaahhiii ho saktaa!! :p :D

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.1help myininaya, please!!!

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.1now explanation will be appreciated. :)

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.1am getting stuck somewhere. and i can't untangle my mind.. :/

ch2831
 2 years ago
Best ResponseYou've already chosen the best response.0Change my answer. 27 in 448 chance that they will all meet, 136 in 448 chance that a and b will meet, 136 in 448 chance that b and c will meet, 136 in 448 chance that a and c will meet. 3*136 2*27= 354 in 448 chance that they will meet at all. Therefore 94 in 448 (you can simplify it) chance that they will not meet at all.

Ishaan94
 2 years ago
Best ResponseYou've already chosen the best response.0Timings of the match doesn't coincide with eachother, so when they enter the stadium they must have only one match to watch, lets they don't watch it together. So, there must be three cases either one of them watches the match or two or none. \[\text{_________________________________________________________________________________}\]Now help me do the math.

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0no one's calling for lgbaaaa :( well i dunno this either...

Mani_Jha
 2 years ago
Best ResponseYou've already chosen the best response.0For each of the three persons, there are two choices  watch the match or not, for each of the seven matches. So, total no of ways in which each one completes the day is 2X2X2..=2^7. Is this right so far?

Mani_Jha
 2 years ago
Best ResponseYou've already chosen the best response.0The total no of choices for the 3 people would be 3X2^7. Atleast I found out the denominator of my fraction..:P

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.1right so far mani, and i seem to be seeing it clearer now.

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.1unhnn....the choices for the three would get multiplied rendering your denominator 2^21, since it is an 'OR' case, where each member may watch a match or not, and each person's choice being an independent event.

Mani_Jha
 2 years ago
Best ResponseYou've already chosen the best response.0oh yeah. you're right. Now let me think how to use the given probability ratio.

Mani_Jha
 2 years ago
Best ResponseYou've already chosen the best response.0@ch2831, where did you get the number 448 from?

arcticf0x
 2 years ago
Best ResponseYou've already chosen the best response.0The names have been badly chosen :P

Mani_Jha
 2 years ago
Best ResponseYou've already chosen the best response.0Yeah, it is. Please explain why you chose that number. To be honest, I didn't understand your answer.

dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.4hmm i'm getting a really small probability here > (5/32)^7 each match is an independent event so you would multiply the probabilities hence raising to 7th power each match has 4 possiblilties None watch: > (1/4)^3 = 1/64 1 watches: > 3*(3/4)*(1/4)^2 = 9/64 2 watches > 3*(3/4)^2*(1/4) = 27/64 All watch > (3/4)^3 = 27/64 so probability less than 2 watch any given match is 10/64 = 5/32

Ishaan94
 2 years ago
Best ResponseYou've already chosen the best response.0Oh so this is how the probability ratio is used

Mani_Jha
 2 years ago
Best ResponseYou've already chosen the best response.0Oh...This topic really isn't made for me :=(

dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.4i believe that is right, the probability you watch is 3 times greater than not watching

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.1@dumbcow .. yayy!!!!!!!!!! you did it i guess!!! yeah he took the ratio thing right too, ishaan!

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.1@arcticf0x , the names have been *purposefully* chosen. :p

Ishaan94
 2 years ago
Best ResponseYou've already chosen the best response.0Nice solution :) #I need to study probability :/
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