anonymous
  • anonymous
how to find nth derivative of sin x
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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saifoo.khan
  • saifoo.khan
- cos x.
.Sam.
  • .Sam.
y=sin(x) y'(x)=cos(x) y''(x)=-sin(x) y'''(x)=-cos(x) y''''(x)=sin(x), so at the 4th derivative, we're back to sin(x)
anonymous
  • anonymous
i want nth derivative ... bro

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anonymous
  • anonymous
Yn for sin (ax+b) ???
anonymous
  • anonymous
sin ( n pie/2 + x )
anonymous
  • anonymous
No..thats not correct pavan
anonymous
  • anonymous
Explain why it is not
anonymous
  • anonymous
For nth derivative...if n is odd- derivative would be - a^n( cos(ax+b)) and if n is even- derivative would be a^n ( sin(ax+b))
anonymous
  • anonymous
The answer I said was for sin x.If you meant the nth derivative of Sin(ax+b),then you're right
anonymous
  • anonymous
well..yes in that case..you are right.

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