At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
the highest value of principal quantum number gives the period number
half filled or full filled,and correspondingly its stability.
How many elements should be there in total if all th 7s 7p 6d and 5f block are to be full
help me here please ^^^
doesnt 7s fulfilled mean that 1s,2s,3s,4s...6s fulfilled..how can 7s be filled wothout these getting filled earlier
ok ok I thought that it was saying to calculate elements in nly these 7s, 7p ...
i think the question meant how many elements would you find in the periodic table if elements were discovered upto that which has filled 5f shell
so 7*2 means - 2 for 1s, 2 for 2s, 2 for 3s, 2 for 4s, 2 for 5s, 2 for 6s, 2 for 7s =14 14 for 4f , 14 for 5f = 28 10 for 3d, 4d, 5d, 6d = 40 6 for 2p, 3p, 4p, 5p, 6p, 7p= 36 TOTAL = 118 elemets I GUESS IS THE CORECT ANSWER
M I RIGHT??
totally....i think i should relearn multiplication..silly mistakes i make.but yes, i think you are correct.my final answer came same as you
NO NO u was mistaken in taking 5 * 14 while there are no f orbital for 1, 2, 3 so it was 2*14 and u took 7*6 but 1 dont have p orb so it was 6* 6 also 6*d should have taken as 4*6 bcz thr are no d orbital for 1,2,
although Im not sure abt my answer...I would lke anyone to verify my answer
instead of writing 5f, i wrote 5*14. and to do shortcut,u make some mistakes
i didnot make the mistake of couting d... i know which n corresponds to which l....although it may look different, i know it was computation mistake...i had it right in my mind........so i realize that jaldi karne se galti hota hai
ok ok r u sure ki this answer is right??
checked again and again this time..dont feel so...feel pretty confidant...which class are u in...ur question gave me an opportunity for revising atomic structure. thanks
my 11 board exams going on and am from kolkata. if u have more questions,do ask.
yes i will... i will for sure ... i am dumb in my studies...specially in chem
doesnt matter. do differently in 12. u sound to do goog
ok tell me n, l,m for 3px orbital my answer is n=3 , l= 0,1,2 and m= 1, 2, -1, -2 m I right???
for m , its -l to +l , that includes 0 . so -2,-1-0,1,2. remember that number of values of m is equal to 2l +1
obvoiusly -0 =0
also magnetic spin quanum no= +1/2 , -1/2 and what u said above that m= 0,1,2 ,-1,-2 OK? ha ha -0 =0
it may sound simple,but one day i was asked to prove -0 = 0 . even that + - we use has a lot of mathematically hifis attached
m= 2l +1 . so there should be 5 values of m , putting l =2 and m ranges from -l to +l
ok next one is- here 0.280g of Fe is treated with excess of (BaOH)2. Cal the weight of precipitate. eqn is Fe2 (SO4)3 + 3Ba(OH)2 ---> 2Fe (OH)3 + 3BaSO4 (at mas Fe-56, Ba-137, O-16 H-1 S-32)
would u prefer i do by unitary method,or ratio method, or poac theory or number of equivalence
my answr is 1.165 gm please chk , and do wth any method i just need to chk answers
0.28 gram ferrous sulphate or fe?
Ferric ions sorry
0.28 gram of ferric sulphate then?
this is the point to think---> 0.280 of Ferric ions is reacted .and we have to find BaSO4 (which is precipitate)
mine is coming 0.1498. dont your book have ans at the back
no please share steps
number of equivalence for any reaction is constant. number of equivalence = weight of sample divided by equivalent weight. do it in your calculator. valency factor ferric sulfate is 6 and that for ferric hydroxide is 3
ok i will do later i think i need to re think. now next Determine the molecular formula of a compund which contains 2.19% H, 12.8% C , 85% Br . 1g of compund occupies 119 ml of volume at stp .
take ratio of percentages and atomic weight. then take them to their simple whole number forms. ths gives ratios of atomicities of compoung..i.e emperical formula...