What is the slope of the boundary for y < 3x + 2?
Stacey Warren - Expert brainly.com
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good morning :)
why do you think the answer is 3 ?
Want me to be honest? Im on here this morning for answers because i dont understand this at all :(
Ah, well let's try to fix that then ;)
have you heard of the point-slope form of a line?\[y=mx+b\]?
sorry, that's slope-intercept form
Ive heard of it yes, but do i remember it? No
ok, well\[y=mx+b\]is an equation of a line
in this equation, the slope is represented by \(m\) and the y-intercept is \(b\) (whatever number that is)
|dw:1333030760466:dw|here is an imaginary drawing of \[y=mx+b\] you can see that it intercepts the y-axis at y=b
the slope of the line is m
(btw if m was negative the line would point down)
you have\[y<3x+2\]which is the the set of all points under the line\[y=3x+2\] so that would be the shaded region|dw:1333030953621:dw|we shaded the area \(under\) the line because we have the "less than" symbol <, and the shaded area is where y<3x+2
if we had y>3x+2 we would shade the region \(above\) the line
so you can see that the border, irregardless whether you have\[ymx+b\]\[y\le mx+b\]\[y\ge mx+b\]is always defined by the line\[y=mx+b\]I told you before that \(m\) in this form is the slope
now compare the general formula\[y=mx+b\]with yours\[y=3x+2\]what is the value of \(m\) in your equation?