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 2 years ago
Given the function f(x), the fraction f (x+h)f(x)/h is the difference quotient associated with f. The determination of a function's difference quotient is the first step in determining the function's derivative and is an important topic in Calculus. For each of the following functions determine its difference quotient.
 2 years ago
Given the function f(x), the fraction f (x+h)f(x)/h is the difference quotient associated with f. The determination of a function's difference quotient is the first step in determining the function's derivative and is an important topic in Calculus. For each of the following functions determine its difference quotient.

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JJackers4
 2 years ago
Best ResponseYou've already chosen the best response.1sqrt(x+h)sqrt(x)/h => [(sqrt(x+h)sqrt(x))*(sqrt(x+h)+sqrt(x)]/(h*(sqrt(x+h)+sqrt(x)) => (once cancelled) = h/(h*(sqrt(h+x)+sqrt(x))) = 1/(sqrt(x+h)+sqrt(x)) => (as h>0) = 1/2*sqrt(x) .. sorry this isn't typed up well computer is slow .. 1st part i rationalised the fraction btw. hope this helps
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