anonymous
  • anonymous
if an electron is placed in a uniform electric field, directed east and the magnitude of the field is 2.5 x 10^3 N/C what is the direction and acceleration of the electron? I think I should be using F=qE to get F and then use F=ma to get accel but I am not sure if I can elim q from F=qE or not. Also does the electron move with, or against the field? Thanks.
Physics
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
East direction means +x, so qE<0 (-x) remember that electron charge is negative, so: ma=-qE a=-qE/m , this means that accceleration is directed to west.

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