anonymous
  • anonymous
1
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
remainder is 0 because \[f(-1)=0\]
anonymous
  • anonymous
if you are doing synthetic division, then you are forgetting to substitute the 0 for the x^2 coefficient
anonymous
  • anonymous
\[x^3-4x+1=(x+1)(\text{something})\] and you can find the something either by division or by thinking

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anonymous
  • anonymous
My table looks like this: -1/ 3 -4 -1 _______-3___7 3 -7 6
anonymous
  • anonymous
|dw:1333039280704:dw|
experimentX
  • experimentX
remainder must be zero .. (x+1)(3x^2 - 3x -1)
anonymous
  • anonymous
what dockworker said you have to keep the place for the missing x^2 term
anonymous
  • anonymous
\[3x^3-4x+1=3x^3+0x^2-4x+1\] you have to keep the place
anonymous
  • anonymous
dockworker wrote out the synthetic division correctly
anonymous
  • anonymous
math teacher love to put this on tests and quizzes to see if you are paying attention, so make sure to remember to check for missing terms

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