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This one should be fun: http://dl.dropbox.com/u/12189012/fact.html

Mathematics
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2 137 577 22689565741
it's prime.... ;)
Where did you get those numbers from? And it's not a prime number.

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Other answers:

are you actually serious about solving that....????
I use some algorithms online
I guess you're right: this website is not a serious place. :)
Your algorithms are wrong because the number ends in 7, yet you say that it's divisible by 2. :P
actually this is a nyc place but that no. is a bit too large to solve...
oh yea......so it should be only itself...
This number has only two factors.
yes.....got it
then they have to be 1 and itself and hence its prime...
I already said that the number is not prime!
then how can it have ONLY 2 factors.....1 and itself have to be compulsory factors....
With two factors, I obviously meant to state proper ones (and excluding 1).
Otherwise, the problem would've been trivial, no? ;P
with such a LARGE no. the problem can never be a trivial one.....
2158122193002952449690243008233157266924190689, 24058327474941875553768074062128402939746847713
I said that the problem would have been trivial if it had been a prime.
Zarkon, how did you do that? ;P
I wonder if you wrote a program.
I'm part machine.
so, how do we 'solve' this? o.O
i'm going to write a program to solve this :) and yes, should be fun :D
Not just any program, we need a very fast prime factorization algorithm is required. If you are very confident about your algorithm , you may consider testing it here:www.spoj.pl/problems/FACT2/

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