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What is the equation of the line that passes through (12, 4) and is perpendicular to the graph of y = –1/3x – 2?
 2 years ago
 2 years ago
What is the equation of the line that passes through (12, 4) and is perpendicular to the graph of y = –1/3x – 2?
 2 years ago
 2 years ago

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brinetheryBest ResponseYou've already chosen the best response.1
Look at your slope of that line. The slope is 1/3. In order for your other line to be perpendicular, it needs to be the "negative inverse." That means you have to flip the 1/3 and then multiply it by 1. 1*(3/1) = 3 So you have your point (12,4) and your slope m=3 Plug these values into y=mx+b to get your bvalue (yintercept) After that, you'll have your mvalue and your bvalue. Plug those (only those) into y=mx+b and you'll have the eqn of your perpendicular line.
 2 years ago

brinetheryBest ResponseYou've already chosen the best response.1
Okay, I'll start from here: So you have your point (12,4) and your slope m=3 Plug these values into y=mx+b to get your bvalue (yintercept) 4 = 3*(12) +b b=4 (3)*12=32 m=4 b=32 Plug them into y=mx+b and you have the equation of your line. You're not looking for a point. You're finding an equation.
 2 years ago

brinetheryBest ResponseYou've already chosen the best response.1
Do you know how to plug numbers in to formulas?
 2 years ago

brinetheryBest ResponseYou've already chosen the best response.1
Read through this whole thing then. You won't be able to do these problems if you don't know how to graph or plug numbers in. http://tutorial.math.lamar.edu/Classes/Alg/Lines.aspx
 2 years ago
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