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anonymous
 4 years ago
Using graphing technology, approximate where the graph of y = 5x2 − 3x − 9 crosses the xaxis.
(1.55, 0) and (−1.15, 0)
(1.23, 0) and (−1.26, 0)
(1.32, 0) and (−1.01, 0)
(1.68, 0) and (−1.08, 0)
anonymous
 4 years ago
Using graphing technology, approximate where the graph of y = 5x2 − 3x − 9 crosses the xaxis. (1.55, 0) and (−1.15, 0) (1.23, 0) and (−1.26, 0) (1.32, 0) and (−1.01, 0) (1.68, 0) and (−1.08, 0)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Quadratic formula... a=5 b=3 c=9 Plug them in and you'll get two answers for x. Both yvalues will be 0.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Or do you want me to tell you how to do this on a TI83/84?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I have no idea how to do any of these..:/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do you have a graphing calculator?

agreene
 4 years ago
Best ResponseYou've already chosen the best response.2the link I put is a picture of the graphyou can use it to do the estimation they are asking for.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0a=5 b=3 c=9 Plug them in and you'll get two answers for x. Both yvalues will be 0.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0((3) +/ sqrt((3)^2  4*5*(9)))/(2*5)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(3 +/ (sqrt(9+180))/10 (3+/ sqrt(189))/10 ***THIS MEANS*** x = (3+ sqrt(189))/10 y=0 x = (3sqrt(189))/10 y=0 Is this making sense?
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