A community for students.
Here's the question you clicked on:
 0 viewing
 2 years ago
Using graphing technology, approximate where the graph of y = 5x2 − 3x − 9 crosses the xaxis.
(1.55, 0) and (−1.15, 0)
(1.23, 0) and (−1.26, 0)
(1.32, 0) and (−1.01, 0)
(1.68, 0) and (−1.08, 0)
 2 years ago
Using graphing technology, approximate where the graph of y = 5x2 − 3x − 9 crosses the xaxis. (1.55, 0) and (−1.15, 0) (1.23, 0) and (−1.26, 0) (1.32, 0) and (−1.01, 0) (1.68, 0) and (−1.08, 0)

This Question is Closed

brinethery
 2 years ago
Best ResponseYou've already chosen the best response.1Quadratic formula... a=5 b=3 c=9 Plug them in and you'll get two answers for x. Both yvalues will be 0.

brinethery
 2 years ago
Best ResponseYou've already chosen the best response.1Or do you want me to tell you how to do this on a TI83/84?

mydaddysalineman94
 2 years ago
Best ResponseYou've already chosen the best response.0I have no idea how to do any of these..:/

brinethery
 2 years ago
Best ResponseYou've already chosen the best response.1Do you have a graphing calculator?

agreene
 2 years ago
Best ResponseYou've already chosen the best response.2the link I put is a picture of the graphyou can use it to do the estimation they are asking for.

brinethery
 2 years ago
Best ResponseYou've already chosen the best response.1a=5 b=3 c=9 Plug them in and you'll get two answers for x. Both yvalues will be 0.

brinethery
 2 years ago
Best ResponseYou've already chosen the best response.1((3) +/ sqrt((3)^2  4*5*(9)))/(2*5)

brinethery
 2 years ago
Best ResponseYou've already chosen the best response.1(3 +/ (sqrt(9+180))/10 (3+/ sqrt(189))/10 ***THIS MEANS*** x = (3+ sqrt(189))/10 y=0 x = (3sqrt(189))/10 y=0 Is this making sense?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.