yrivers36
Find the domain and write in interval notation
sqrt of (102x)



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sernst2
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since you can't square a negative number, you must first solve for x

sernst2
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102x=0, 10=2x, x=5

Savvy
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\[x \epsilon[5,\infty)\]

Savvy
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since \[10  2x \ge 0\]

yrivers36
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ok thank you. I thought so but was not sure.

Savvy
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welcome...!!!!

yrivers36
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would it be x is less than or equal to 5