## yrivers36 4 years ago Please help me to understand. y ^(-1/5) I changed problem to 1/y^(1/5) after this point I am not sure how to solve once its in radical form

1. amistre64

its an expression, not an equation

2. amistre64

what constitutes a solution to a statement?

3. Savvy

you cannot solve it any further until and unless it is equal to something...

4. anonymous

guessing y^(1/5)=$\sqrt[5]{y}$

5. Yrivers36

Ok so I did have it right. Thank you so much

6. anonymous

I just changed the form of the equation. hint is look at the fraction and that what the sqrt will be powered to

7. Yrivers36

ok so then it will be the denominator and one the numerator

8. anonymous

for the most part yes.

9. Yrivers36

10. anonymous

y^(1/2)= is just $\sqrt{y}$ because the sqrt is equal to second power that's why if you ever want to get rid of the sqrt just sq it

11. Yrivers36

it was y^(-1/5)

12. anonymous

i know. i was just giving an example

13. Yrivers36

oh ok sorry

14. anonymous

no worries have a good one

15. Yrivers36

you too