## yrivers36 Group Title Please help me to understand. y ^(-1/5) I changed problem to 1/y^(1/5) after this point I am not sure how to solve once its in radical form 2 years ago 2 years ago

1. amistre64 Group Title

its an expression, not an equation

2. amistre64 Group Title

what constitutes a solution to a statement?

3. Savvy Group Title

you cannot solve it any further until and unless it is equal to something...

4. Nismo450Z Group Title

guessing y^(1/5)=$\sqrt[5]{y}$

5. yrivers36 Group Title

Ok so I did have it right. Thank you so much

6. Nismo450Z Group Title

I just changed the form of the equation. hint is look at the fraction and that what the sqrt will be powered to

7. yrivers36 Group Title

ok so then it will be the denominator and one the numerator

8. Nismo450Z Group Title

for the most part yes.

9. yrivers36 Group Title

10. Nismo450Z Group Title

y^(1/2)= is just $\sqrt{y}$ because the sqrt is equal to second power that's why if you ever want to get rid of the sqrt just sq it

11. yrivers36 Group Title

it was y^(-1/5)

12. Nismo450Z Group Title

i know. i was just giving an example

13. yrivers36 Group Title

oh ok sorry

14. Nismo450Z Group Title

no worries have a good one

15. yrivers36 Group Title

you too