anonymous
  • anonymous
.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
inital temperature is time = 0 or x = 0... calculate T(0) = 60*(1/2)^(0/30) + 20
anonymous
  • anonymous
since you're not using logs, are you expected to use the graphing calculator to figure out the time it takes to reach 28 degrees C?
anonymous
  • anonymous
ok, good... i love calculators!!! your initial temp is correct. did you graph the function?

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anonymous
  • anonymous
can you graph it with wolfram?
anonymous
  • anonymous
lemme try...
anonymous
  • anonymous
this is your graph with the line y=28 (the horizontal line). If you look where the two graphs intersect, it occurs somewhere between 85 and 90. http://www.wolframalpha.com/input/?i=graph+y%3D60*%281%2F2%29%5E%28x%2F30%29+%2B+20%2C+y%3D28+intersection
anonymous
  • anonymous
if all we can do is read from the graph, yeah...
anonymous
  • anonymous
but use your TI83 it has an intersection function...
anonymous
  • anonymous
np..
anonymous
  • anonymous
ok, by trial? so |dw:1333069785470:dw| do you mean like that? and using your calculator try different values until you get something somewhere between 85 and 90?
anonymous
  • anonymous
notice, we cannot solve for x here without the use of logs (as you said you cannot use it.)
anonymous
  • anonymous
so can it be 87? because thats what i get when graphed
anonymous
  • anonymous
sure, in fact that's pretty close... |dw:1333070162942:dw|
anonymous
  • anonymous
np

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