when a 75 g mass is suspended from a vertical spring, the spring is stretched from a length of 4.0 cm to a length of 7.0 cm if the mass is pulled downward an additional 10 cm what is the total work done against the spring force.

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w = kd ; w = 75, d = 3
k = 75/3 = 25
F(x) = 25x
\[\int_{7}^{7+10}25x\ dx\]

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