anonymous
  • anonymous
Find the center & radius for the following: 1. 2x^2+2y^2=72 2. (x-3)^2+(y-1)^2=4 3. (x-5)^2+(y+2)^2=49 4. (y-4)^2+(x-10)^2=64
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
dumbcow
  • dumbcow
these are all circles the circle equation is: (x-h)^2 +(y-k)^2 = r^2 center: (h,k) radius is r
anonymous
  • anonymous
1)Center is (0,0) radius=6 2)Center is (3,1) radius=2 3)Center is (5,-2) radius=7 4)Center is (10,4) radius=8
anonymous
  • anonymous
Your amazing! i have a few more.

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anonymous
  • anonymous
1. (x^2-6x+9)+(y^2+8y+16)=1
anonymous
  • anonymous
Center is (3,-4) radius=1
anonymous
  • anonymous
2. x^2+12x+y^2-8y=-27
anonymous
  • anonymous
Center is (-6,4) radius=5
anonymous
  • anonymous
Write an equation for the circle with center at (3,-4) and with (2,-1) a point on the circle.
anonymous
  • anonymous
omg, amazinggggg. (:
anonymous
  • anonymous
\[x^2+y^2-6x+8y+15=0\]
anonymous
  • anonymous
My multiple choice answers are: (x-2)^2+(y+1)^2=1 (x+2)^2+(y-1)^2=10 (x-3)^2+(y+4)^2=10 (x-3)^2+(y+4)^2=5 (x+3)^2+(y-4)^2=100
anonymous
  • anonymous
C
anonymous
  • anonymous
Your so smart.
anonymous
  • anonymous
Glad to help

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