anonymous
  • anonymous
Please don't solve! Just need help! Consider the equation y=150(2^x). 1) Make a table of x and y-values for whole number x-values from 0 to 5. 2) What do the numbers 150 and 2 in the equation tell you about the relationship? Need help with both 1 and 2!! Please help and explain like you are explaining it to a really slow person.....Cuz im slow....
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
ok replace x by 0 and what do you get?
anonymous
  • anonymous
150...
anonymous
  • anonymous
\[y=150\times 2^x\] is the equation, replace x by 0 and get \[y=150\times 2^0\] recall that it is always true that \[b^0=1\] so you have \[y=150\times 1=150\]

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anonymous
  • anonymous
the number 150 tells you what you get when you start at x = 0, so if you are going to graph, you know that the point (0,150) will be on the graph
anonymous
  • anonymous
now replace x by 1 and get \[y=150\times 2^1=150\times 2=300\] so we know that every increase by 1 in x will double the y value
anonymous
  • anonymous
and double again when we replace x by 2 to get \[y=150\times 2^2=150\times 4=600\]
anonymous
  • anonymous
What would the setup of the table be? Like this?|dw:1333071851284:dw|
anonymous
  • anonymous
you can set it up like that, yes
anonymous
  • anonymous
actually no, not a good idea!
anonymous
  • anonymous
or this?|dw:1333071909174:dw|
anonymous
  • anonymous
put the x on the left and the y on the right
anonymous
  • anonymous
im sorry but how would i set it up? im very confused...
anonymous
  • anonymous
ohh!!!
anonymous
  • anonymous
|dw:1333071964330:dw|
anonymous
  • anonymous
oh thank you!
anonymous
  • anonymous
|dw:1333072008375:dw|
anonymous
  • anonymous
sorry it is so ugly, but you get the picture right?
anonymous
  • anonymous
thank you! i am now finished with my hw thanks to you!
anonymous
  • anonymous
@blackrose.ritock Remember previous post: 5,000 is initial number and factor is 1.5!
anonymous
  • anonymous
yes i remember!
anonymous
  • anonymous
Similarly with 150 and 2 here! Now, the problem apply exponential formula, not manual anymore!
anonymous
  • anonymous
thanks everyone!|dw:1333072317598:dw|
anonymous
  • anonymous
What's a pleasure :D
anonymous
  • anonymous
:)
anonymous
  • anonymous
BTW, don't forget to click on "Good Answer" to recognize the solvers' help!

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