anonymous
  • anonymous
A sample of Geometry class final exam grades are as follows: 80, 85, 72, 76, 95 Find the variance. 1) 7.96 2) 49.23 3) 63.44 4) 6.72
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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amistre64
  • amistre64
for variance we need the mean first
anonymous
  • anonymous
what mean means
amistre64
  • amistre64
\[var=\frac{\sum (x-\bar x)^2}{n-1}\]

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More answers

amistre64
  • amistre64
your asking a question that presupposes you know what a mean is; its the average of the given data
anonymous
  • anonymous
add it all together then divide by 5
amistre64
  • amistre64
yes, and that is what we use to get a final answer for variance.
amistre64
  • amistre64
(mean - x)^2 = (x-mean)^2 so i see no need to be strict about that part of it tho
anonymous
  • anonymous
its 332
amistre64
  • amistre64
hmm, im not so sure about that, let me do some calculations in a general sense
anonymous
  • anonymous
the answer is 49.23
amistre64
  • amistre64
mean = (80+85+72+76+95)/5 = 81.6 (81.6-80)^2+(81.6-85)^2+(81.6-72)^2+(81.6-76)^2+(81.6-95)^2 = 317.2 317.2/(5-1) = 79.3 as a variance
anonymous
  • anonymous
thats not an answer choice
amistre64
  • amistre64
then the answer choices are wrong.
amistre64
  • amistre64
http://www.wolframalpha.com/input/?i=%7B80%2C+85%2C+72%2C+76%2C+95%7D variance is the square of the sample standard deviation: (8.905)^2 = abt 76.29

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