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Kushashwa_ravi Group Title

hey what is bump in method ?

  • 2 years ago
  • 2 years ago

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  1. Tributized Group Title
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    i think it's a function

    • 2 years ago
  2. 142343 Group Title
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    i Think that they are put less questions so there is less time to get metals and stuff and this is not a math question.

    • 2 years ago
  3. Kushashwa_ravi Group Title
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    sketch the graph of y=sin(x+pi/4)

    • 2 years ago
  4. Kushashwa_ravi Group Title
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    can u help me in this question

    • 2 years ago
  5. Tributized Group Title
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    is this mathematics?

    • 2 years ago
  6. Kushashwa_ravi Group Title
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    yes

    • 2 years ago
  7. Tributized Group Title
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    i searched Bump in wikipedia, it says --->a mathematical function which has a non-empty bounded support

    • 2 years ago
  8. Tributized Group Title
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    but i don't know really.

    • 2 years ago
  9. Kushashwa_ravi Group Title
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    ok well can u help me that question : sketch the graph of y=sin(x+pi/4)

    • 2 years ago
  10. Kushashwa_ravi Group Title
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    i am not able to draw the graph of it Amplitude = 1 , but what is period . can any1 tell me amistre sir ?

    • 2 years ago
  11. amistre64 Group Title
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    its the graph of y=sin(x) shifted pi/4 units to the left

    • 2 years ago
  12. Kushashwa_ravi Group Title
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    sir why it is shifted left

    • 2 years ago
  13. amistre64 Group Title
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    becasue when we change the value associated with "x" that tends to slide the graph left or right

    • 2 years ago
  14. Kushashwa_ravi Group Title
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    sir please if u don;t mind can u draw the graph for my help please

    • 2 years ago
  15. amistre64 Group Title
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    draw me the sin(x) basic graph and ill see what i can do

    • 2 years ago
  16. Kushashwa_ravi Group Title
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    ok sir

    • 2 years ago
  17. Kushashwa_ravi Group Title
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    |dw:1333120673494:dw|

    • 2 years ago
  18. amistre64 Group Title
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    |dw:1333120794494:dw|

    • 2 years ago
  19. Kushashwa_ravi Group Title
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    siw why have u denoted 3pi/2 as pi and 7pi/4 as 2 pi approx. ?

    • 2 years ago
  20. Kushashwa_ravi Group Title
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    sir*

    • 2 years ago
  21. Kushashwa_ravi Group Title
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    3pi/4*

    • 2 years ago
  22. amistre64 Group Title
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    i used your graph, and shifted it all to the left by pi/4 and then recalculated the intercepts accordingly to its new values

    • 2 years ago
  23. amistre64 Group Title
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    what was pi is now pi-pi/4 = 3pi/4 what was 2pi is now 2pi-pi/4 = 7pi/4

    • 2 years ago
  24. amistre64 Group Title
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    what was 0, is now 0 - pi/4 = -pi/4

    • 2 years ago
  25. Kushashwa_ravi Group Title
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    k sir thanks sir if the question was y=sin(x-pi/4) then i would have to shift pi/4 to left instead of right ?

    • 2 years ago
  26. Kushashwa_ravi Group Title
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    i mean the original orgin would be right to the new origin obtained

    • 2 years ago
  27. amistre64 Group Title
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    the operator sign can be a bit misguided. always go the opposite direction of the sign

    • 2 years ago
  28. Kushashwa_ravi Group Title
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    k sir

    • 2 years ago
  29. amistre64 Group Title
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    x - pi/4 would shift in the+ direction x + pi/4 would shift in the - direction

    • 2 years ago
  30. Kushashwa_ravi Group Title
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    sir one more problem there was a question in my book : sketch the graph of the following pairs of funcitons on the same axes: 1) y=sinx , y=sin(x+pi/4)

    • 2 years ago
  31. Kushashwa_ravi Group Title
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    sir what u drew is it the answer of this question , i would have just to draw it by dooted lines to differenciate

    • 2 years ago
  32. amistre64 Group Title
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    so we would sketch (sketch is an approximate drawing as opposed to an exact drawing) the y=sin(x) and then copy it pi/4 to the left yes, dotted would be fine, or a different color I was stuck in post limbo ,,,,

    • 2 years ago
  33. Kushashwa_ravi Group Title
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    no problem sir , well 10000000000000000s of medals for your helping mind. thanks a lot sir i would keep posting the questions if i would get confused in any topic here . thanks again sir

    • 2 years ago
  34. amistre64 Group Title
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    good luck :)

    • 2 years ago
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