hey what is bump in method ?

- anonymous

hey what is bump in method ?

- katieb

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- anonymous

i think it's a function

- anonymous

i Think that they are put less questions so there is less time to get metals and stuff and this is not a math question.

- anonymous

sketch the graph of y=sin(x+pi/4)

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- anonymous

can u help me in this question

- anonymous

is this mathematics?

- anonymous

yes

- anonymous

i searched Bump in wikipedia, it says
--->a mathematical function which has a non-empty bounded support

- anonymous

but i don't know really.

- anonymous

ok well can u help me that question : sketch the graph of y=sin(x+pi/4)

- anonymous

i am not able to draw the graph of it Amplitude = 1 , but what is period .
can any1 tell me amistre sir ?

- amistre64

its the graph of y=sin(x) shifted pi/4 units to the left

- anonymous

sir why it is shifted left

- amistre64

becasue when we change the value associated with "x" that tends to slide the graph left or right

- anonymous

sir please if u don;t mind can u draw the graph for my help please

- amistre64

draw me the sin(x) basic graph and ill see what i can do

- anonymous

ok sir

- anonymous

|dw:1333120673494:dw|

- amistre64

|dw:1333120794494:dw|

- anonymous

siw why have u denoted 3pi/2 as pi and 7pi/4 as 2 pi approx. ?

- anonymous

sir*

- anonymous

3pi/4*

- amistre64

i used your graph, and shifted it all to the left by pi/4 and then recalculated the intercepts accordingly to its new values

- amistre64

what was pi is now pi-pi/4 = 3pi/4
what was 2pi is now 2pi-pi/4 = 7pi/4

- amistre64

what was 0, is now 0 - pi/4 = -pi/4

- anonymous

k sir thanks sir if the question was y=sin(x-pi/4) then i would have to shift pi/4 to left instead of right ?

- anonymous

i mean the original orgin would be right to the new origin obtained

- amistre64

the operator sign can be a bit misguided. always go the opposite direction of the sign

- anonymous

k sir

- amistre64

x - pi/4 would shift in the+ direction
x + pi/4 would shift in the - direction

- anonymous

sir one more problem there was a question in my book :
sketch the graph of the following pairs of funcitons on the same axes:
1) y=sinx , y=sin(x+pi/4)

- anonymous

sir what u drew is it the answer of this question , i would have just to draw it by dooted lines to differenciate

- amistre64

so we would sketch (sketch is an approximate drawing as opposed to an exact drawing) the y=sin(x) and then copy it pi/4 to the left
yes, dotted would be fine, or a different color
I was stuck in post limbo ,,,,

- anonymous

no problem sir , well 10000000000000000s of medals for your helping mind. thanks a lot sir
i would keep posting the questions if i would get confused in any topic here . thanks again sir

- amistre64

good luck :)

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