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anonymous
 4 years ago
hey what is bump in method ?
anonymous
 4 years ago
hey what is bump in method ?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think it's a function

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i Think that they are put less questions so there is less time to get metals and stuff and this is not a math question.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sketch the graph of y=sin(x+pi/4)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can u help me in this question

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i searched Bump in wikipedia, it says >a mathematical function which has a nonempty bounded support

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but i don't know really.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok well can u help me that question : sketch the graph of y=sin(x+pi/4)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i am not able to draw the graph of it Amplitude = 1 , but what is period . can any1 tell me amistre sir ?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3its the graph of y=sin(x) shifted pi/4 units to the left

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sir why it is shifted left

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3becasue when we change the value associated with "x" that tends to slide the graph left or right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sir please if u don;t mind can u draw the graph for my help please

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3draw me the sin(x) basic graph and ill see what i can do

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1333120673494:dw

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3dw:1333120794494:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0siw why have u denoted 3pi/2 as pi and 7pi/4 as 2 pi approx. ?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3i used your graph, and shifted it all to the left by pi/4 and then recalculated the intercepts accordingly to its new values

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3what was pi is now pipi/4 = 3pi/4 what was 2pi is now 2pipi/4 = 7pi/4

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3what was 0, is now 0  pi/4 = pi/4

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0k sir thanks sir if the question was y=sin(xpi/4) then i would have to shift pi/4 to left instead of right ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i mean the original orgin would be right to the new origin obtained

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3the operator sign can be a bit misguided. always go the opposite direction of the sign

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3x  pi/4 would shift in the+ direction x + pi/4 would shift in the  direction

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sir one more problem there was a question in my book : sketch the graph of the following pairs of funcitons on the same axes: 1) y=sinx , y=sin(x+pi/4)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sir what u drew is it the answer of this question , i would have just to draw it by dooted lines to differenciate

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3so we would sketch (sketch is an approximate drawing as opposed to an exact drawing) the y=sin(x) and then copy it pi/4 to the left yes, dotted would be fine, or a different color I was stuck in post limbo ,,,,

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no problem sir , well 10000000000000000s of medals for your helping mind. thanks a lot sir i would keep posting the questions if i would get confused in any topic here . thanks again sir
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