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AlexisDelgado

  • 4 years ago

Multiply and simplify: (4 + v8) (4- v8)

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  1. Muhammad_Nauman_Umair
    • 4 years ago
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    is it v^8?

  2. jhonyy9
    • 4 years ago
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    16-64v^2

  3. jhonyy9
    • 4 years ago
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    16(1-4v^2)

  4. Muhammad_Nauman_Umair
    • 4 years ago
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    as, a^2-b^2=(a+b)(a-b)

  5. vi3tbloodxx
    • 4 years ago
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    FOIL (4+v8) (4- v8) =16 - 4v8 + 4v8 - 8 = 8

  6. Muhammad_Nauman_Umair
    • 4 years ago
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    then, =4^2-(v^8)^2 =16-v^16

  7. Kreshnik
    • 4 years ago
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    @vi3tbloodxx you're wrong... (4+v8) (4- v8) =16 - 4v8 + 4v8 - 8 = 8 it should be (4+v8) (4- v8) =16 - 4v8 + 4v8 - 64v^2 =4^2-(8v)^2 so from here we can see that there's no need to multiply and simplify... just use difference of binom formula : a^2-b^2 =(a+b)(a-b) \[\LARGE a^2-b^2=(a-b)(a+b)\]

  8. vi3tbloodxx
    • 4 years ago
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    a^2−b^2=(a−b)(a+b)\ in this equation (4+v8) (4- v8) a = 4 and b = v8 4^2 - (v8)^2 gives 16 - 8 = 8

  9. Kreshnik
    • 4 years ago
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    @vi3tbloodxx Still don't get what you're trying to say...O_o where's "v" how come (v8)^2=8 ???

  10. vi3tbloodxx
    • 4 years ago
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    the v stands for the square root of 8. When squaring a square root the result is the number inside of the square root.

  11. vi3tbloodxx
    • 4 years ago
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    v cannot be a variable due to the fact that variables stands behind the number. Also from the poster previous post, she been using "v" as a square root notation.

  12. Kreshnik
    • 4 years ago
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    hold on... is \[\LARGE v8=\sqrt8\] or \[\LARGE v8=v8\] ?? "v" is a square root or just a letter?? !

  13. Kreshnik
    • 4 years ago
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    auff... not your fault , I misunderstood ! I apologize , you're right , the answer is 8 :(

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