anonymous
  • anonymous
Multiply and simplify: (4 + v8) (4- v8)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
is it v^8?
jhonyy9
  • jhonyy9
16-64v^2
jhonyy9
  • jhonyy9
16(1-4v^2)

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Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
as, a^2-b^2=(a+b)(a-b)
anonymous
  • anonymous
FOIL (4+v8) (4- v8) =16 - 4v8 + 4v8 - 8 = 8
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
then, =4^2-(v^8)^2 =16-v^16
anonymous
  • anonymous
@vi3tbloodxx you're wrong... (4+v8) (4- v8) =16 - 4v8 + 4v8 - 8 = 8 it should be (4+v8) (4- v8) =16 - 4v8 + 4v8 - 64v^2 =4^2-(8v)^2 so from here we can see that there's no need to multiply and simplify... just use difference of binom formula : a^2-b^2 =(a+b)(a-b) \[\LARGE a^2-b^2=(a-b)(a+b)\]
anonymous
  • anonymous
a^2−b^2=(a−b)(a+b)\ in this equation (4+v8) (4- v8) a = 4 and b = v8 4^2 - (v8)^2 gives 16 - 8 = 8
anonymous
  • anonymous
@vi3tbloodxx Still don't get what you're trying to say...O_o where's "v" how come (v8)^2=8 ???
anonymous
  • anonymous
the v stands for the square root of 8. When squaring a square root the result is the number inside of the square root.
anonymous
  • anonymous
v cannot be a variable due to the fact that variables stands behind the number. Also from the poster previous post, she been using "v" as a square root notation.
anonymous
  • anonymous
hold on... is \[\LARGE v8=\sqrt8\] or \[\LARGE v8=v8\] ?? "v" is a square root or just a letter?? !
anonymous
  • anonymous
auff... not your fault , I misunderstood ! I apologize , you're right , the answer is 8 :(

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