Here's the question you clicked on:
calyne
find f'(x): f(x) = x*sqrt(2-x^2)
looks like a product and a chain wrapped together with some other basics thrown in for good measure
f(x) = x*sqrt(2-x^2) f'(x) = (x*sqrt(2-x^2))' f'(x) = x'sqrt(2-x^2) + x*sqrt(2-x^2)' f'(x) = x'sqrt(2-x^2) + x*sqrt(2-x^2)' * (2-x^2)'
\[x \sqrt{2-x ^{2}} - (x ^{2}/\sqrt{2-x ^{2}})\]
(2-2x^2)/sqrt(2-x^2) thanks i got it tho