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calyne

  • 4 years ago

find f'(x): f(x) = x*sqrt(2-x^2)

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  1. amistre64
    • 4 years ago
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    looks like a product and a chain wrapped together with some other basics thrown in for good measure

  2. amistre64
    • 4 years ago
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    f(x) = x*sqrt(2-x^2) f'(x) = (x*sqrt(2-x^2))' f'(x) = x'sqrt(2-x^2) + x*sqrt(2-x^2)' f'(x) = x'sqrt(2-x^2) + x*sqrt(2-x^2)' * (2-x^2)'

  3. Savvy
    • 4 years ago
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    \[x \sqrt{2-x ^{2}} - (x ^{2}/\sqrt{2-x ^{2}})\]

  4. calyne
    • 4 years ago
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    (2-2x^2)/sqrt(2-x^2) thanks i got it tho

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