anonymous
  • anonymous
why e^lnf(x) = f(x), where can I FIND the proof of it?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
e^lnf(x)=e^log(e)(f(x))=f(x)
anonymous
  • anonymous
that's it, is it a proof? it just flew over my head :|
TuringTest
  • TuringTest
by definition of the lgarithm\[\log_ax=y\iff x=a^y= a^{\log_a x}\]

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anonymous
  • anonymous
ok, that right
TuringTest
  • TuringTest
no ngoc... just restated the problem and proved nothing no offense...
Savvy
  • Savvy
let \[y = e^{lnf(x)}\] taking log on both sides... \[\ln y = \ln e^{lnf(x)}\] since\[lnx^m = mlnx\] so \[lny = lnf(x)lne\] also ln(e) = 1 so lny = lnf(x) so y = f(x) but \[y = e^{lnf(x)}\] so \[f(x) = e^{lnf(x)}\]
anonymous
  • anonymous
ok, the same
anonymous
  • anonymous
it is definition
anonymous
  • anonymous
thanx @ savy
anonymous
  • anonymous
@Savvy very rigour proof
TuringTest
  • TuringTest
did you follow mine wounded tiger? it may not be as elaborate, but I think it is solid
Savvy
  • Savvy
lol...your welcome dude...

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