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MaryJSmithBest ResponseYou've already chosen the best response.1
8cos35 degrees 8sin 35 degrees sin35 degrees/8 cos35 degrees/8
 2 years ago

saifoo.khanBest ResponseYou've already chosen the best response.2
\[\sin \theta = \frac{opposite}{hypotenuse}\]
 2 years ago

MaryJSmithBest ResponseYou've already chosen the best response.1
idk what all that means..
 2 years ago

saifoo.khanBest ResponseYou've already chosen the best response.2
dw:1333128731997:dwDont sleep in class. ;)
 2 years ago

MaryJSmithBest ResponseYou've already chosen the best response.1
I'm home schooled.. I can't sleep in class , haha . I just don't understand this stuff & I have HORRIBLE memory :) Ha !
 2 years ago

saifoo.khanBest ResponseYou've already chosen the best response.2
lol. Ok. this is easy i can teach you. :)
 2 years ago

MaryJSmithBest ResponseYou've already chosen the best response.1
So what is it exactly that I'm supposed to do here ??
 2 years ago

saifoo.khanBest ResponseYou've already chosen the best response.2
There are three basic ratios. Sin ratio, cos ratio, tan ratio. you have to remember these.. Not them down somewhere.
 2 years ago

saifoo.khanBest ResponseYou've already chosen the best response.2
dw:1333128936512:dw
 2 years ago

saifoo.khanBest ResponseYou've already chosen the best response.2
dw:1333129034555:dw
 2 years ago

saifoo.khanBest ResponseYou've already chosen the best response.2
Now these are the three sides. now it depends upon the question which two ratio you have to use.. you have to judge it by yourself.
 2 years ago

saifoo.khanBest ResponseYou've already chosen the best response.2
Now in your question.. you are given hypotenuse and you have to find the opposite side.. so u will be using sin ratio.
 2 years ago

MaryJSmithBest ResponseYou've already chosen the best response.1
i still don't get it though . like , what #'s do i plug in & where ?? it's so confusing to me!!
 2 years ago

inkyvoydBest ResponseYou've already chosen the best response.0
Ok, so the basic idea is that if you have a right angle, and You know the second angle, you know the ratio of the two sides. Now all of the trig functions essentially take in an angle, and out put a ratio.
 2 years ago

MaryJSmithBest ResponseYou've already chosen the best response.1
i'm still confused :(
 2 years ago

inkyvoydBest ResponseYou've already chosen the best response.0
Do you want to talk it over in chat?
 2 years ago

MaryJSmithBest ResponseYou've already chosen the best response.1
No.. too overwhelming . Just mssg me .
 2 years ago

inkyvoydBest ResponseYou've already chosen the best response.0
Can we do something like tiny chat? Messaging is too slow. If you have a skype, you could chat with me there (or create an anonymous one)
 2 years ago

MaryJSmithBest ResponseYou've already chosen the best response.1
i cant , im also takin a test & i can only be on here & my test (im bein supervised)
 2 years ago

inkyvoydBest ResponseYou've already chosen the best response.0
Wait, you are allowed to go here and on your test?
 2 years ago

inkyvoydBest ResponseYou've already chosen the best response.0
Alright, Trigonometry is like an extension of triangle congruence.
 2 years ago

inkyvoydBest ResponseYou've already chosen the best response.0
For triangle similarity, we can prove that two triangles are similar given certain info (SAS, AA, SSS, etc). But if they are similar, then how can we figure out the side lengths they have?
 2 years ago

inkyvoydBest ResponseYou've already chosen the best response.0
The answer is that we use trigonometry. The basic idea of trig is that in a right triangle where we know all the degree measures, we can determine the ratio between the sides.
 2 years ago

inkyvoydBest ResponseYou've already chosen the best response.0
Tell me if you are following what I'm saying, ok
 2 years ago

MaryJSmithBest ResponseYou've already chosen the best response.1
I'm not.. haha sorry . I am so confused !! I'm a visual/audio learner..
 2 years ago

inkyvoydBest ResponseYou've already chosen the best response.0
ok, who is supervising you? I have file that will help you a lot, but it's for a geometry software called "GeoGebra"
 2 years ago

inkyvoydBest ResponseYou've already chosen the best response.0
Alright, take a look at this file. Tell me if it helps.
 2 years ago

MaryJSmithBest ResponseYou've already chosen the best response.1
I'm just gonna guess cos theres like 4 or 5 probs like this & I have 15 mins to finish 20 more problems !!!!!
 2 years ago

inkyvoydBest ResponseYou've already chosen the best response.0
sigh. if they are typable, put them into wolfram alpha dot com or something,
 2 years ago

MikellaalbertsonBest ResponseYou've already chosen the best response.0
So what's the answer
 11 months ago
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