MaryJSmith
What is the length of the portion BC of the cloth?
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MaryJSmith
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MaryJSmith
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8cos35 degrees
8sin 35 degrees
sin35 degrees/8
cos35 degrees/8
saifoo.khan
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use sin ratio.
MaryJSmith
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idk what that is..
saifoo.khan
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\[\sin \theta = \frac{opposite}{hypotenuse}\]
MaryJSmith
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idk what all that means..
saifoo.khan
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|dw:1333128731997:dw|Dont sleep in class. ;)
MaryJSmith
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I'm home schooled.. I can't sleep in class , haha . I just don't understand this stuff & I have HORRIBLE memory :) Ha !
saifoo.khan
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lol.
Ok. this is easy i can teach you. :)
MaryJSmith
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So what is it exactly that I'm supposed to do here ??
saifoo.khan
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There are three basic ratios.
Sin ratio, cos ratio, tan ratio.
you have to remember these..
Not them down somewhere.
MaryJSmith
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okay..
saifoo.khan
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|dw:1333128936512:dw|
saifoo.khan
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|dw:1333129034555:dw|
saifoo.khan
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Now these are the three sides.
now it depends upon the question which two ratio you have to use..
you have to judge it by yourself.
saifoo.khan
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Now in your question.. you are given hypotenuse and you have to find the opposite side..
so u will be using sin ratio.
MaryJSmith
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i still don't get it though . like , what #'s do i plug in & where ?? it's so confusing to me!!
inkyvoyd
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Ok, so the basic idea is that if you have a right angle, and You know the second angle, you know the ratio of the two sides. Now all of the trig functions essentially take in an angle, and out put a ratio.
MaryJSmith
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i'm still confused :(
inkyvoyd
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Do you want to talk it over in chat?
MaryJSmith
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No.. too overwhelming . Just mssg me .
inkyvoyd
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Can we do something like tiny chat? Messaging is too slow. If you have a skype, you could chat with me there (or create an anonymous one)
MaryJSmith
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i cant , im also takin a test & i can only be on here & my test (im bein supervised)
inkyvoyd
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Wait, you are allowed to go here and on your test?
MaryJSmith
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Yes
inkyvoyd
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Alright, Trigonometry is like an extension of triangle congruence.
inkyvoyd
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*triangle similarity
inkyvoyd
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For triangle similarity, we can prove that two triangles are similar given certain info (SAS, AA, SSS, etc). But if they are similar, then how can we figure out the side lengths they have?
MaryJSmith
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idk..
inkyvoyd
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The answer is that we use trigonometry. The basic idea of trig is that in a right triangle where we know all the degree measures, we can determine the ratio between the sides.
inkyvoyd
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Tell me if you are following what I'm saying, ok
MaryJSmith
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I'm not.. haha sorry . I am so confused !! I'm a visual/audio learner..
inkyvoyd
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ok, who is supervising you? I have file that will help you a lot, but it's for a geometry software called "GeoGebra"
MaryJSmith
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i have geogebra
inkyvoyd
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Alright, take a look at this file. Tell me if it helps.
MaryJSmith
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I'm just gonna guess cos theres like 4 or 5 probs like this & I have 15 mins to finish 20 more problems !!!!!
inkyvoyd
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sigh. if they are typable, put them into wolfram alpha dot com or something,
Mikellaalbertson
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So what's the answer