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JerJason
A wet bar of soap slides freely down a ramp 8.5m long inclined at 8.0 degrees. How long does it take to reach the bottom? Assume kinetic friction is .50.
Hi \[mgsin \theta-\mu _{k}mg \cos \theta=ma \rightarrow a=g(\sin \theta-\mu _{k} \cos \theta)\]so use this to find time of motion:\[x=(1/2)at^2\rightarrow t=\sqrt{2x/a}\] where "x"is length of ramp
oh wow, I had the above formula correct, I just needed that second formula. Thanks.