anonymous
  • anonymous
Find the lateral area for the cylinder with the given measurement. r = 4, h = 5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
kymber
  • kymber
Lateral Area = 2πrh so A = 2(3.14)(4)(5)
anonymous
  • anonymous
thankz but i don't think that works:/ |dw:1333130511151:dw|
kymber
  • kymber
What do you mean? That's the formula D:

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saifoo.khan
  • saifoo.khan
Saw that vid?
anonymous
  • anonymous
AHHHHHHHHHH:O IDK AM DUMB
kymber
  • kymber
What o_o
saifoo.khan
  • saifoo.khan
Everyone's dumb in the beginning so dont worry. :)
anonymous
  • anonymous
BAHAH I WAS BORN DUMB & AM STILL DUMB..............
saifoo.khan
  • saifoo.khan
Me too. i even didn't knew how to speak.
anonymous
  • anonymous
hahahha that's evryone
saifoo.khan
  • saifoo.khan
LOL. do everyone's dumb. you aren't the only one.
anonymous
  • anonymous
thank god i was thinking i was :/
saifoo.khan
  • saifoo.khan
2 pi r h it's the formula for it
anonymous
  • anonymous
|dw:1333130829727:dw|
Directrix
  • Directrix
The lateral area of a right circular cylinder is found by multiplying the circumference of its base times its height. That formula is given above by kymber. The result is 40 π.
anonymous
  • anonymous
thank you @Directrix :D
kymber
  • kymber
|dw:1333130925888:dw|
kymber
  • kymber
Y U no thank kymbah? D:<
anonymous
  • anonymous
BAHAHA THATNKS ALOT THAT WAS SUPPOST TO BE ME:/
kymber
  • kymber
:O you're an alien?!
Directrix
  • Directrix
From CoC: Don't spam! Common forms of spam include: •Posting a reply that is not relevant to the topic of discussion within that question.
anonymous
  • anonymous
|dw:1333131011878:dw| YOU IN JAIL
saifoo.khan
  • saifoo.khan
Oh. lol. |dw:1333131022521:dw|
kymber
  • kymber
Why am I in jail ;(
anonymous
  • anonymous
CAUSE YOU KILLED MY FAT STICK FIGURE:/
kymber
  • kymber
|dw:1333131091044:dw|
saifoo.khan
  • saifoo.khan
lol
anonymous
  • anonymous
Ok everyone, think that's enough, eh?
anonymous
  • anonymous
|dw:1333131256127:dw|
kymber
  • kymber
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saifoo.khan
  • saifoo.khan
LOL

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