anonymous
  • anonymous
Can someone PLEASEEEE explain to me how to do this??? I am SOO confused!!
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
jhonyy9
  • jhonyy9
park-library will be =sqrt116 park-football field --- will be =sqrt(116+100) = sqrt216
campbell_st
  • campbell_st
there are 2 similar triangles by angle angle test as shown in the diagram |dw:1333135297820:dw| the side PH is common to both triangles and can used to find the ratio of corresponding sides in similar triangles x/14 = 4/x \[x^2 = 56\] \[x = \sqrt{56}\] Now use pythagoras' theorem to find the Park, Library distance. The right triangle has sides 4 and \[x = \sqrt{56}\] then \[LP^2 = (\sqrt{56})^2 - 4^2\] \[LP = \sqrt{40} = 2\sqrt{10}\] Same method for Football field - Park Sides 14 and \[x = \sqrt{56}\] \[FP^2 = 14^4 - (\sqrt{56})^2\] \[FP = \sqrt{140} = 2\sqrt{35}\] I hope this make sense

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Directrix
  • Directrix
Theorem: If the altitude is drawn to the hypotenuse of a right triangle, the length of the altitude is the geometric mean between the lengths of the segments of the hypotenuse. In part A, the length from the park to the library (denote as PL) is the geometric mean between 10 and 4. That gives: 10 is to PL as PL is to 4 10 / PL = PL / 4 (PL)^2 = 40 PL = 2√10
Directrix
  • Directrix
Part B) Theorem: If an altitude is drawn to the hypotenuse of a right triangle, either leg of the triangle is the geometric mean between the length of the hypotenuse and the segment of the hypotenuse adjacent to that leg. From the park to the football field (denote as PF) is a leg of the largest right triangle. 10 is to PF as PF is to 14 10/PF = PF/14 PF = 2√ 35
Directrix
  • Directrix
Those results appear to be the fourth answer option.
anonymous
  • anonymous
i got it! thanks guys, that helped a lot!

Looking for something else?

Not the answer you are looking for? Search for more explanations.