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A_Level_Student
A horizontal force of 20N just prevents a mask of 2kg from sliding down a rough plane inclined at 45 degrees to the horizontal.Find the coefficient of friction.
Hi from below fig we can analyze forces and solve question: |dw:1333139120501:dw|
analyze forces respect to this coordinate |dw:1333139185052:dw|
i have a similar diagram but how can we analyse the forces
so:in direction of normal to incline:\[N-Fsin \theta =mgcos \theta\]& in direction of down of incline:\[mgsin \theta-Fcos \theta-\mu _{s}.N=ma=0\]so if you solve 2 equation for mu yields:\[(-Fcos \theta+mgsin \theta)/(Fsin \theta+mgcos \theta)=\mu _{s}\]
hey hi! u draw the diagram again with the resolving of vectors can u do that? wat is ur name?
u oght be analyze forces respect to that coordinate |dw:1333221355385:dw|
bisho, were u comfortable in resolving those horizontal force and mg down the slope?
|dw:1333350119161:dw|
|dw:1333455525796:dw| |dw:1333455661277:dw| where Ff is frictional force sum up all these forces acting on the body i have shown different diagrams to avoid confusion i want the body to be in rest so all those vertical forces (on bothe sides of incline) and horizonatal forces(acting on both sides shud be equal)