Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

A horizontal force of 20N just prevents a mask of 2kg from sliding down a rough plane inclined at 45 degrees to the horizontal.Find the coefficient of friction.

Physics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
Hi from below fig we can analyze forces and solve question: |dw:1333139120501:dw|
analyze forces respect to this coordinate |dw:1333139185052:dw|
i have a similar diagram but how can we analyse the forces

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

so:in direction of normal to incline:\[N-Fsin \theta =mgcos \theta\]& in direction of down of incline:\[mgsin \theta-Fcos \theta-\mu _{s}.N=ma=0\]so if you solve 2 equation for mu yields:\[(-Fcos \theta+mgsin \theta)/(Fsin \theta+mgcos \theta)=\mu _{s}\]
hey hi! u draw the diagram again with the resolving of vectors can u do that? wat is ur name?
u oght be analyze forces respect to that coordinate |dw:1333221355385:dw|
bisho, were u comfortable in resolving those horizontal force and mg down the slope?
|dw:1333350119161:dw|
|dw:1333455525796:dw| |dw:1333455661277:dw| where Ff is frictional force sum up all these forces acting on the body i have shown different diagrams to avoid confusion i want the body to be in rest so all those vertical forces (on bothe sides of incline) and horizonatal forces(acting on both sides shud be equal)

Not the answer you are looking for?

Search for more explanations.

Ask your own question