The function satisfies the identity
f(x) + f(y) = f(x+y) (1)
for all x and y. Show that 2f(x) = f(2x) and deduce that f '' (0) = 0. By considering the Maclaurin series for f(x),
find the most general function that satisfies (1).
[Do not consider issues of existence or convergence of Maaclaurin series in this question.]

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First, it is clear to you that f(2x) = 2f(x), yes?

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