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anonymous
 4 years ago
The remedy is experience.. And I don't have any..
Help please ?
anonymous
 4 years ago
The remedy is experience.. And I don't have any.. Help please ?

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PaxPolaris
 4 years ago
Best ResponseYou've already chosen the best response.0First find the length of BD using △BCD

PaxPolaris
 4 years ago
Best ResponseYou've already chosen the best response.0using Pythagorean theorem

PaxPolaris
 4 years ago
Best ResponseYou've already chosen the best response.0\[BD^2=18^2+24^2\]\[\therefore BD=\sqrt{18^2+24^2}\] (you can remove the common factor of 18 and 24 out to make the math easier)\[\implies BD = 6\sqrt{3^2+4^2}=6\sqrt{25}=\Large 30 ft.\]

PaxPolaris
 4 years ago
Best ResponseYou've already chosen the best response.0Then to find AD you need to know trigonometry ....OR atleast the ratios of the sides of 306090 triangles.

PaxPolaris
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1333147962445:dw In 306090 triangles the ratios of the sides is always \[\Large 1:\sqrt3:2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Cool... Now what do I do with that ?

PaxPolaris
 4 years ago
Best ResponseYou've already chosen the best response.0△ABD is a 306090 triangle.... if you know one side(BD) you can find the others

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so do i do 30*the sqr rt of 3 ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That would be 52 (rounded up)

PaxPolaris
 4 years ago
Best ResponseYou've already chosen the best response.0AD is smaller than BD... ...If the side opposite the 30deg (smallest) angle is length 1(smallest side) ..........then the side opposite the 60deg angle is sqrt3

PaxPolaris
 4 years ago
Best ResponseYou've already chosen the best response.0\[\Large {BD \over AD} = \frac {\sqrt3} 1\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so would you do 30*the square root of 3 divided by 2 then ? That comes out to be 26 (rounded up)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Dude , I'm so confused . Can you just give me the answer ? Lol . I'll ask my teacher about all this crap on Monday .

PaxPolaris
 4 years ago
Best ResponseYou've already chosen the best response.0\[{ 30 \over AD} = {\sqrt3 \over 1}\] \[AD = {30 \over \sqrt 3} = \Large 10\sqrt3\ ft.\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks (what does 3sf mean ?)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.03 significant figures (1, 7 and 3)

PaxPolaris
 4 years ago
Best ResponseYou've already chosen the best response.0ignore significant figures if you don't know what it means... by seventeenish, I meant 10*sqrt3 is around 17

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok. 17.3 (1dp / 1 decimal point)
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