Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
MaryJSmith
Group Title
The remedy is experience.. And I don't have any..
Help please ?
 2 years ago
 2 years ago
MaryJSmith Group Title
The remedy is experience.. And I don't have any.. Help please ?
 2 years ago
 2 years ago

This Question is Closed

PaxPolaris Group TitleBest ResponseYou've already chosen the best response.0
First find the length of BD using △BCD
 2 years ago

PaxPolaris Group TitleBest ResponseYou've already chosen the best response.0
using Pythagorean theorem
 2 years ago

PaxPolaris Group TitleBest ResponseYou've already chosen the best response.0
\[BD^2=18^2+24^2\]\[\therefore BD=\sqrt{18^2+24^2}\] (you can remove the common factor of 18 and 24 out to make the math easier)\[\implies BD = 6\sqrt{3^2+4^2}=6\sqrt{25}=\Large 30 ft.\]
 2 years ago

MaryJSmith Group TitleBest ResponseYou've already chosen the best response.0
Thanks :)
 2 years ago

PaxPolaris Group TitleBest ResponseYou've already chosen the best response.0
Then to find AD you need to know trigonometry ....OR atleast the ratios of the sides of 306090 triangles.
 2 years ago

MaryJSmith Group TitleBest ResponseYou've already chosen the best response.0
Do what ?
 2 years ago

PaxPolaris Group TitleBest ResponseYou've already chosen the best response.0
dw:1333147962445:dw In 306090 triangles the ratios of the sides is always \[\Large 1:\sqrt3:2\]
 2 years ago

MaryJSmith Group TitleBest ResponseYou've already chosen the best response.0
Cool... Now what do I do with that ?
 2 years ago

PaxPolaris Group TitleBest ResponseYou've already chosen the best response.0
△ABD is a 306090 triangle.... if you know one side(BD) you can find the others
 2 years ago

MaryJSmith Group TitleBest ResponseYou've already chosen the best response.0
so do i do 30*the sqr rt of 3 ?
 2 years ago

MaryJSmith Group TitleBest ResponseYou've already chosen the best response.0
That would be 52 (rounded up)
 2 years ago

PaxPolaris Group TitleBest ResponseYou've already chosen the best response.0
AD is smaller than BD... ...If the side opposite the 30deg (smallest) angle is length 1(smallest side) ..........then the side opposite the 60deg angle is sqrt3
 2 years ago

MaryJSmith Group TitleBest ResponseYou've already chosen the best response.0
I'm confused again..
 2 years ago

PaxPolaris Group TitleBest ResponseYou've already chosen the best response.0
\[\Large {BD \over AD} = \frac {\sqrt3} 1\]
 2 years ago

MaryJSmith Group TitleBest ResponseYou've already chosen the best response.0
so would you do 30*the square root of 3 divided by 2 then ? That comes out to be 26 (rounded up)
 2 years ago

MaryJSmith Group TitleBest ResponseYou've already chosen the best response.0
Dude , I'm so confused . Can you just give me the answer ? Lol . I'll ask my teacher about all this crap on Monday .
 2 years ago

PaxPolaris Group TitleBest ResponseYou've already chosen the best response.0
\[{ 30 \over AD} = {\sqrt3 \over 1}\] \[AD = {30 \over \sqrt 3} = \Large 10\sqrt3\ ft.\]
 2 years ago

AsianDuck Group TitleBest ResponseYou've already chosen the best response.1
17.3 (3sf)
 2 years ago

MaryJSmith Group TitleBest ResponseYou've already chosen the best response.0
thanks (what does 3sf mean ?)
 2 years ago

AsianDuck Group TitleBest ResponseYou've already chosen the best response.1
3 significant figures (1, 7 and 3)
 2 years ago

PaxPolaris Group TitleBest ResponseYou've already chosen the best response.0
ignore significant figures if you don't know what it means... by seventeenish, I meant 10*sqrt3 is around 17
 2 years ago

AsianDuck Group TitleBest ResponseYou've already chosen the best response.1
ok. 17.3 (1dp / 1 decimal point)
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.