anonymous
  • anonymous
Hey, just trying to understand the intuition of functions a bit better. f(x) = -5 if x = -2, f(x) = -3x^2 + 4 otherwise. The 4 is the y-intercept, and the -3x squared is the slope, right? Is the -3x squared because the parabola is symmetrical?
Mathematics
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chestercat
  • chestercat
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anonymous
  • anonymous
You can get the slope by differentiating\[-3x^2 + 4\] to get the slope function as: \[-6x\]
saifoo.khan
  • saifoo.khan
Can you please rephrase your question?
anonymous
  • anonymous
What is the range? but i'd like to know if the 4 is the y-intercept and the -3x^2 is the slope, and if possible can you show me on a graph?

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saifoo.khan
  • saifoo.khan
-3x^2 is NOT the slope.
anonymous
  • anonymous
4 is the y-intercept because at x = 0, f(x) = -3(0)^2 + 4 = 4 The slope is -6x, have you use differentiation before?
saifoo.khan
  • saifoo.khan
you can find the slope of the curve by dy/dx. (if you have studied calc)
anonymous
  • anonymous
no not yet, AsianDuck
anonymous
  • anonymous
Ah, i'm just starting calc, that's prob why i don't really get the intuition yet
saifoo.khan
  • saifoo.khan
y = mx + b here you can apply the logic that "m" is the slope. but u have a quadratic equation here. where the slope will change on every step.
anonymous
  • anonymous
can you please explain differentiation?
saifoo.khan
  • saifoo.khan
http://www.youtube.com/watch?v=rAof9Ld5sOg
anonymous
  • anonymous
but if f(x) = -3x^2 + 4 (wouldn't that count as y = mx + b) with the -3x being the slope??
saifoo.khan
  • saifoo.khan
you have a QUADRATIC EQUATION sir. with "x^2" whereas in linear equation there is "NO x^2" there's only "x"
anonymous
  • anonymous
ah okay :D thank you
saifoo.khan
  • saifoo.khan
any more confusions? i can feel the happiness.

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