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mathsucks16

  • 4 years ago

help me create an example? i did the word part but i need an example for each

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  1. mathsucks16
    • 4 years ago
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    here are the questions with my answers: 1. If I know the lengths of two sides of a right triangle, how do I find the third? Pythagorean Theorem; a^2 + b^2 = c^2 2. Could I find the two missing side lengths of a right triangle if I only know one side length and one angle measure (other than the 90 degree angle)? yes. Law of Sines; sin(a)/A = sin(b)/B = sin(c)/C where a,b,c are the angles of the triangle and A, B, C are the projected sides. 3. Could I find the two missing angle measures if I know some of the side lengths of a right triangle? Use the theorem to find the lengths of triangle and apply them to the Law of Sines. You will need to have at least 2 lengths known. 4. What makes a triangle a “special” right triangle? How can special right triangles help me find side lengths? Special right triangles have set ratios for the lengths of each side of the triangle.

  2. phi
    • 4 years ago
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    In 4. are they asking about 30-60-90 or 45-45-90 triangles? Examples for 1) use the standard 3-4-5 right triangle. label two of the legs and mark the third unknown

  3. mathsucks16
    • 4 years ago
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    in number four it doesnt spicifically state anything

  4. phi
    • 4 years ago
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    You can use a 30-60-90 as an example in 4. label the longest side 1, the side opposite 30 = 1/2 and the remaining side sqrt(3)/2

  5. phi
    • 4 years ago
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    For 2. use a 30-60-90 triangle. label the 30 deg angle as known, and the side opposite it as 1/2 show you can find the hypotenuse: h/sin(90) = 0.5 / sin(30) and show you can find the 2nd side: x/sin(60) = 0.5/ sin(30)

  6. phi
    • 4 years ago
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    for 3) label the two legs 3 and 4. (that will make the hyp 5) then use sin(A)/3 = sin(90)/5 to find the A opposite the side with length 3 sin(B)/4 = sin(90)/5 to find the angle B opposite the side with length 4

  7. mathsucks16
    • 4 years ago
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    so for number one just put this,

  8. mathsucks16
    • 4 years ago
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    |dw:1333150994154:dw|

  9. phi
    • 4 years ago
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    yes. then label h . then write 3^2+4^2= h^2 9+16= h^2 , 25=h^2 , 5= h

  10. mathsucks16
    • 4 years ago
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    so this will be my drawing and then just right the equation you wrote|dw:1333151971349:dw|

  11. phi
    • 4 years ago
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    yes. That will be an example of 1. If I know the lengths of two sides of a right triangle, how do I find the third?

  12. mathsucks16
    • 4 years ago
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    and number two would be like this,|dw:1333152465897:dw| and include this equation h/sin(90) = 0.5 / sin(30), 2nd side: x/sin(60) = 0.5/ sin(30)

  13. phi
    • 4 years ago
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    Sorry I missed your post. The question is 2. Could I find the two missing side lengths of a right triangle if I only know one side length and one angle measure (other than the 90 degree angle)? So you need a right triangle. know one side and one angle measure so |dw:1333153485440:dw|

  14. mathsucks16
    • 4 years ago
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    ok i will use that, should i include this too, include this equation h/sin(90) = 0.5 / sin(30), 2nd side: x/sin(60) = 0.5/ sin(30)

  15. phi
    • 4 years ago
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    except I would change the letters to whatever you use as labels for each side. for the posted picture 0.5/sin(30)= c/sin(90) and 0.5/sin(30)= a/sin(60)

  16. mathsucks16
    • 4 years ago
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    ok

  17. phi
    • 4 years ago
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    btw, you should change your name to mathisfun16

  18. mathsucks16
    • 4 years ago
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    lol ill think about it, my problem is i always have rude math teachers and the material stays in my head for a moment then i cant remember anything

  19. phi
    • 4 years ago
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    Yes, there is a lot of memorizing of facts, and methods and definitions. Almost as bad as French, where it seems they have a different word for everything.

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