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here are the questions with my answers: 1. If I know the lengths of two sides of a right triangle, how do I find the third? Pythagorean Theorem; a^2 + b^2 = c^2 2. Could I find the two missing side lengths of a right triangle if I only know one side length and one angle measure (other than the 90 degree angle)? yes. Law of Sines; sin(a)/A = sin(b)/B = sin(c)/C where a,b,c are the angles of the triangle and A, B, C are the projected sides. 3. Could I find the two missing angle measures if I know some of the side lengths of a right triangle? Use the theorem to find the lengths of triangle and apply them to the Law of Sines. You will need to have at least 2 lengths known. 4. What makes a triangle a “special” right triangle? How can special right triangles help me find side lengths? Special right triangles have set ratios for the lengths of each side of the triangle.
In 4. are they asking about 30-60-90 or 45-45-90 triangles? Examples for 1) use the standard 3-4-5 right triangle. label two of the legs and mark the third unknown
in number four it doesnt spicifically state anything
You can use a 30-60-90 as an example in 4. label the longest side 1, the side opposite 30 = 1/2 and the remaining side sqrt(3)/2
For 2. use a 30-60-90 triangle. label the 30 deg angle as known, and the side opposite it as 1/2 show you can find the hypotenuse: h/sin(90) = 0.5 / sin(30) and show you can find the 2nd side: x/sin(60) = 0.5/ sin(30)
for 3) label the two legs 3 and 4. (that will make the hyp 5) then use sin(A)/3 = sin(90)/5 to find the A opposite the side with length 3 sin(B)/4 = sin(90)/5 to find the angle B opposite the side with length 4
so for number one just put this,
yes. then label h . then write 3^2+4^2= h^2 9+16= h^2 , 25=h^2 , 5= h
so this will be my drawing and then just right the equation you wrote|dw:1333151971349:dw|
yes. That will be an example of 1. If I know the lengths of two sides of a right triangle, how do I find the third?
and number two would be like this,|dw:1333152465897:dw| and include this equation h/sin(90) = 0.5 / sin(30), 2nd side: x/sin(60) = 0.5/ sin(30)
Sorry I missed your post. The question is 2. Could I find the two missing side lengths of a right triangle if I only know one side length and one angle measure (other than the 90 degree angle)? So you need a right triangle. know one side and one angle measure so |dw:1333153485440:dw|
ok i will use that, should i include this too, include this equation h/sin(90) = 0.5 / sin(30), 2nd side: x/sin(60) = 0.5/ sin(30)
except I would change the letters to whatever you use as labels for each side. for the posted picture 0.5/sin(30)= c/sin(90) and 0.5/sin(30)= a/sin(60)
btw, you should change your name to mathisfun16
lol ill think about it, my problem is i always have rude math teachers and the material stays in my head for a moment then i cant remember anything
Yes, there is a lot of memorizing of facts, and methods and definitions. Almost as bad as French, where it seems they have a different word for everything.