anonymous
  • anonymous
Let P a point outside the line XY, PO a perpendicular from P to XY, and PZ any line drawn from P to XY. Prove that PZ is not perpendicular to XY
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
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anonymous
  • anonymous
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anonymous
  • anonymous
A triangle can not have more than one right angle.

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anonymous
  • anonymous
Well I know that, but that sounds like a theorem and then I would have to prove it too. So double work =/
anonymous
  • anonymous
- Extend PO to P', so OP' = OP - Drawn P'Z - POP' is a line. - Then PZP' is not a line - then angle P'ZP does not have colinear sides.
anonymous
  • anonymous
On the other side - OP = OP' - OZ = OZ - triangle OPZ = triange OZP' - then angle OZP = angle OZP' - and angle OZP = (1/2)*angle P'ZP
anonymous
  • anonymous
I'm stuck there =/
anonymous
  • anonymous
you can try: PZO is a right triangle. and since POZ is a right triangle, OZP cannot be another right angle because then the sum of the two angles will be 180. and that leaves 0 degrees for the third angle.
anonymous
  • anonymous
That is a good Idea dpalnc but I haven't proof yet that the sum of the angles on an right triangle is 360ยบ. Then I can't use it.
anonymous
  • anonymous
hmm... can you prove by contradiction?
anonymous
  • anonymous
Well I don't know how to prove by contradiction yet. I'm a newbie on the proving world =P
anonymous
  • anonymous
I don't think I should prove that kind of things, but the goal(of the book i'm studying with) is to develop the geometry from just a bunch of postulates.
anonymous
  • anonymous
proof by contradiction is kinda like what I first suggested. you take something that is obviously false and assume it to be true. and by the end of the proof you end up with concluding something ridiculous. so the assumption must be false.
anonymous
  • anonymous
anyway, that's cool that you develop geometry from scratch.
anonymous
  • anonymous
do you have the parallel postulate then?
anonymous
  • anonymous
mmm I don't think so what is that postulate?
TuringTest
  • TuringTest
you meant the sum of the angles in a triangle is \(180^{\circ}\) you want a proof for that? because if you accept that we can prove your thingy by contradiction easily
anonymous
  • anonymous
I don't want a proof of that @TuringTest. The thing is that on the book I'm reading proves this in the way I wrote down. The problem is that I don't understand the proof. =(
anonymous
  • anonymous
In other words I don't get why it concludes that is true after that series of propositions that I know are true.
TuringTest
  • TuringTest
ok, so can we accept that a triangle must have 3 angles that add to 180 ?
anonymous
  • anonymous
Yes if I accept that the proof is very easy. But my goal by now, is not to prove it but understand the proof I just copy.
TuringTest
  • TuringTest
let us assume that PZ is perpendicular to XY then PZ and OP can never intersect this contradicts the assumption that we drew PZ by connecting XY to P hence PZ is not perpendicular to XY
TuringTest
  • TuringTest
proof 2: let us call the triangle formed by the three line segments OPZ we know that
anonymous
  • anonymous
That's impressive @TurinTest!
TuringTest
  • TuringTest
thanks, but they are both two very basic proofs by contradiction a little practice is all that's required

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