Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Let P a point outside the line XY, PO a perpendicular from P to XY, and PZ any line drawn from P to XY. Prove that PZ is not perpendicular to XY

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

|dw:1333151007374:dw|
|dw:1333151163362:dw|
A triangle can not have more than one right angle.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Well I know that, but that sounds like a theorem and then I would have to prove it too. So double work =/
- Extend PO to P', so OP' = OP - Drawn P'Z - POP' is a line. - Then PZP' is not a line - then angle P'ZP does not have colinear sides.
On the other side - OP = OP' - OZ = OZ - triangle OPZ = triange OZP' - then angle OZP = angle OZP' - and angle OZP = (1/2)*angle P'ZP
I'm stuck there =/
you can try: PZO is a right triangle. and since POZ is a right triangle, OZP cannot be another right angle because then the sum of the two angles will be 180. and that leaves 0 degrees for the third angle.
That is a good Idea dpalnc but I haven't proof yet that the sum of the angles on an right triangle is 360ยบ. Then I can't use it.
hmm... can you prove by contradiction?
Well I don't know how to prove by contradiction yet. I'm a newbie on the proving world =P
I don't think I should prove that kind of things, but the goal(of the book i'm studying with) is to develop the geometry from just a bunch of postulates.
proof by contradiction is kinda like what I first suggested. you take something that is obviously false and assume it to be true. and by the end of the proof you end up with concluding something ridiculous. so the assumption must be false.
anyway, that's cool that you develop geometry from scratch.
do you have the parallel postulate then?
mmm I don't think so what is that postulate?
you meant the sum of the angles in a triangle is \(180^{\circ}\) you want a proof for that? because if you accept that we can prove your thingy by contradiction easily
I don't want a proof of that @TuringTest. The thing is that on the book I'm reading proves this in the way I wrote down. The problem is that I don't understand the proof. =(
In other words I don't get why it concludes that is true after that series of propositions that I know are true.
ok, so can we accept that a triangle must have 3 angles that add to 180 ?
Yes if I accept that the proof is very easy. But my goal by now, is not to prove it but understand the proof I just copy.
let us assume that PZ is perpendicular to XY then PZ and OP can never intersect this contradicts the assumption that we drew PZ by connecting XY to P hence PZ is not perpendicular to XY
proof 2: let us call the triangle formed by the three line segments OPZ we know that
That's impressive @TurinTest!
thanks, but they are both two very basic proofs by contradiction a little practice is all that's required

Not the answer you are looking for?

Search for more explanations.

Ask your own question