Identify the discontinuities, graph, and find the zeros of the rational function
f(x) = (4x^2-36x)/(x-9)
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definitely at x=9 you have a discontinuity (removable)
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Can I have, like, the whole equation? My teacher didn't explain anything and I get absolutely nothing.
now that the function is factored, do you see where the zeros will occur? and what the graph will look like?
Are the zeros 9?
but we have a discontinuity there. so it can't be 9... look at the other factor.
your graph will actually look exaclty like the line y = 4x with the restriction that there is no value for y at x = 9. this is what they call a "hole" in the graph (discontinuity).
notice the x-9 from the top and bottom cancel?