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Let\[y=x^p(1+x)^q\]find\[y^{(p+q)}\]

Mathematics
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that's the (p+q)th derivative by the way Sorry that I have to go soon, but I look forward to seeing your responses when I return.
ln(y) = ln(x^p) + ln(1+x)^q y'/y = p/x + q/(1+x) hmm
i think the answer is just (p+q)!

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Other answers:

since the highest power of x will be x^(p+q), and all the other powers of x will become 0 after P+q derivatives.
sounds plausible to me
hint:(Leibniz' theorem/ binomial stuff)
at least in MIT's solution I'd like to see others
lol, id like to see mits solution :)
I'll send it to you....
im curious, what class is this problem from?
OCW calc I
Ahh, okay. Thank you. :)
http://en.wikipedia.org/wiki/Leibniz_rule_(generalized_product_rule)

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