Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

TuringTestBest ResponseYou've already chosen the best response.0
that's the (p+q)th derivative by the way Sorry that I have to go soon, but I look forward to seeing your responses when I return.
 2 years ago

amistre64Best ResponseYou've already chosen the best response.1
ln(y) = ln(x^p) + ln(1+x)^q y'/y = p/x + q/(1+x) hmm
 2 years ago

joemath314159Best ResponseYou've already chosen the best response.2
i think the answer is just (p+q)!
 2 years ago

joemath314159Best ResponseYou've already chosen the best response.2
since the highest power of x will be x^(p+q), and all the other powers of x will become 0 after P+q derivatives.
 2 years ago

amistre64Best ResponseYou've already chosen the best response.1
sounds plausible to me
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.0
hint:(Leibniz' theorem/ binomial stuff)
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.0
at least in MIT's solution I'd like to see others
 2 years ago

amistre64Best ResponseYou've already chosen the best response.1
lol, id like to see mits solution :)
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.0
I'll send it to you....
 2 years ago

AccessDeniedBest ResponseYou've already chosen the best response.0
im curious, what class is this problem from?
 2 years ago

AccessDeniedBest ResponseYou've already chosen the best response.0
Ahh, okay. Thank you. :)
 2 years ago

Mr.MathBest ResponseYou've already chosen the best response.0
http://en.wikipedia.org/wiki/Leibniz_rule_(generalized_product_rule)
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.