ABCD is a square, M the half point of AB. With center on AB an arc is described that cuts AD in Q and BC in P. Prove that triangle MBP = triangle MAQ

- anonymous

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- anonymous

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- anonymous

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- anonymous

this will help u a lot!!

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- anonymous

Thank you.

- experimentX

prove those two triangles are congruent
1) both 90 degree
2) midpoint bisects so bases are equal
3) radii of circle are equal ... equal hypotenuse

- anonymous

I think I need to prove another theorem first, But it's totally right what you say experimentX, thankyou!

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