anonymous
  • anonymous
graph the function y=(3/2)cos (x+2pi/3) ?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
well there are two types of method solving method 1 3cos(2pi/3x-pi/6), factor out the lcf in order to get x alone. 3cos[2pi/3(x-1/4)], where b is 2pi/3. The formula to find the period of a sine or cosine equation is 2pi/B, so 2pi/2pi/3=3. The period is 3. The Amplitude for the cosine is [-3,3] because the coefficiant tells us to multiply the Range of the Cosine function [-1,1] by 3. In order to find the Y-int let x=0 to get 3cos(-pi\6), then you get 2.59807. When y=0, x=1 solving method 2 Begin with a simpler function and subject it to transformations. Leave out the y-intercept until the end. y = 3cos(2πx/3 - π/6) = y = 3cos[(2π/3)(x - 1/4)] y = cos(x) x-intercepts: π/2, 3π/2, 5π/2, 7π/2, 9π/2,... maxima: 0, 2π, 4π,... minima: π, 3π, 5π,... y = cos[(2π/3)x] The graph is scaled horizontally by ratio 3/(2π). x-intercepts: 3/4, 9/4, 15/4, 21/4, 27/4,... maxima: 0, 3, 6,... minima: 3/2, 9/2, 15/2,... cos[(2π/3)(x - 1/4)] The graph is translated to the right by 1/4 unit. x-intercepts: 1, 5/2, 4, 11/2, 7,... maxima: 1/4, 13/4, 25/4,... minima: 7/4, 19/4, 31/4,... 3cos[(2π/3)(x - 1/4)] This final transformation gives you an amplitude of 3. The x-intercepts and extrema have the same horizontal position. The maxima have y-coordinate 3. The minima have y-coordinate -3. Now for the y-intercept, substitute x = 0. y = 3cos[(2π/3)(0 - 1/4)] = y = 3cos(-π/6) = 3√(3)/2
anonymous
  • anonymous
can u show me the graph?

Looking for something else?

Not the answer you are looking for? Search for more explanations.