## calyne Group Title Find y' by implicit differentiation: 1/x + 1/y = 1 2 years ago 2 years ago

$\frac{1}{x}+\frac{1}{y}=1$ $x^{-1}+y^{-1}=1$ -------------------------------------- Differentiate, $-x^{-2}-y^{-2}(y')=0$ $-y^{-2}(y')=x^{-2}$ $(y')=\frac{x^{-2}}{-y^{-2}}$ $y'=-\frac{y^2}{x^2}$