## anonymous 4 years ago Find y' by implicit differentiation: 1/x + 1/y = 1

1. .Sam.

$\frac{1}{x}+\frac{1}{y}=1$ $x^{-1}+y^{-1}=1$ -------------------------------------- Differentiate, $-x^{-2}-y^{-2}(y')=0$ $-y^{-2}(y')=x^{-2}$ $(y')=\frac{x^{-2}}{-y^{-2}}$ $y'=-\frac{y^2}{x^2}$

2. anonymous

Okay so now: Solve the equation explicitly for y and differentiate to get y' in terms of x.