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## calyne Group Title Find y' by implicit differentiation: 1/x + 1/y = 1 2 years ago 2 years ago

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1. .Sam. Group Title

$\frac{1}{x}+\frac{1}{y}=1$ $x^{-1}+y^{-1}=1$ -------------------------------------- Differentiate, $-x^{-2}-y^{-2}(y')=0$ $-y^{-2}(y')=x^{-2}$ $(y')=\frac{x^{-2}}{-y^{-2}}$ $y'=-\frac{y^2}{x^2}$

2. calyne Group Title

Okay so now: Solve the equation explicitly for y and differentiate to get y' in terms of x.