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Is this it?
\[x^{4/5} \over x^{1/3}\]

yes

http://tutorial.math.lamar.edu/Classes/Alg/IntegerExponents.aspx
Property 3.
a^m/a^n = a^(m-n)

Get both fractions so that they have a common denominator and then subtract them.

is it x 4/15?

\[x^{4/5}x^{-1/3}\]

I think like x^7/15

x 3/2?

here are my options:
x3/2 x7/15 x17/15 x4/15

bri is right the exponent is 4/5 - 1/3

so 3/2

remember how to subtract fractions? Least common denominator?

fancy way of saying make the numbers on the bottom the same before you can subtract

What's 12/15 - 5/15?

7/15 okay i understand now

Make sure you know how to add and subtract fractions, it's very important.

good luck!