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Kreshnik Group Title

\[\LARGE f'(x)=x^2+3x \;\; ,\;\; f(1)=5\;\;\;\;\Longrightarrow f(2)=?\] I need some hints

  • 2 years ago
  • 2 years ago

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  1. SUROJ Group Title
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    f(x) can be obtained by integration........then use f(1) to find value of c, then find f(2)

    • 2 years ago
  2. Rohangrr Group Title
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    ya suroj ur correctt

    • 2 years ago
  3. SUROJ Group Title
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    got it?

    • 2 years ago
  4. Kreshnik Group Title
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    \[\LARGE f(x)=\frac13 x^3 +\frac32 x^2 \;\;\;\;??\]

    • 2 years ago
  5. SUROJ Group Title
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    you left +C at the end

    • 2 years ago
  6. SUROJ Group Title
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    you need to add +C at end because it is integration

    • 2 years ago
  7. SUROJ Group Title
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    indefinite integration

    • 2 years ago
  8. Kreshnik Group Title
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    ok but... I need to firnd f(2) then how??

    • 2 years ago
  9. SUROJ Group Title
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    on the second condition when x=1, y=5, you see , put those values and get c

    • 2 years ago
  10. Kreshnik Group Title
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    \[\LARGE \int\limits x^2+3x \;dx = \frac13 x^3+\frac32x^2+C\]

    • 2 years ago
  11. SUROJ Group Title
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    put the c back on f(x) and get complete f(x) equation and then find f(2)

    • 2 years ago
  12. SUROJ Group Title
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    yes

    • 2 years ago
  13. Rohangrr Group Title
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    correct

    • 2 years ago
  14. Kreshnik Group Title
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    how can I know what the value of C is ??

    • 2 years ago
  15. Kreshnik Group Title
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    I see it you told me before... let me try, I'll see what I can do :D

    • 2 years ago
  16. SUROJ Group Title
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    see second condition f(1) is 5 than mean when x=1 , y=5

    • 2 years ago
  17. SUROJ Group Title
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    see f(x) is what you get by integration

    • 2 years ago
  18. SUROJ Group Title
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    because you integrate f'(x)

    • 2 years ago
  19. SUROJ Group Title
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    did you catch it?

    • 2 years ago
  20. Kreshnik Group Title
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    is C=19/6 ??

    • 2 years ago
  21. Kreshnik Group Title
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    I'm still dizzy ! O_O

    • 2 years ago
  22. SUROJ Group Title
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    yes you got it

    • 2 years ago
  23. SUROJ Group Title
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    now put that C back in f(x)

    • 2 years ago
  24. SUROJ Group Title
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    got it?

    • 2 years ago
  25. Kreshnik Group Title
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    ahh yeah... now I'll do it thank you very much ;)

    • 2 years ago
  26. SUROJ Group Title
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    no problem lol

    • 2 years ago
  27. JoshDavoll Group Title
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    \[f \left( x \right) = x ^{2} + 3x\] \[f \left( 1 \right) = 1^{2} + 3 \times 1 = 5\] \[f \left( 2 \right) = 2^{2} + 3 \times 2 = 10\] simple.

    • 2 years ago
  28. JoshDavoll Group Title
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    @kreshnik another simple way to do something.

    • 2 years ago
  29. Kreshnik Group Title
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    @JoshDavoll WRONG... the answer IS \[\frac{71}{6}\] !! Thanks for the help !

    • 2 years ago
  30. Kreshnik Group Title
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    hahaha... obviously , you mus be 10-12 years ... LOL

    • 2 years ago
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