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mckayla_04

  • 2 years ago

Rationalize the denominator of radical 18 over radical 3?

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  1. Rohangrr
    • 2 years ago
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    .. √18 / √3 = [ √18 * √3 ] / [ √3 * √3 ] = [ √(18 * 3) ] / 3 = [ √(6 * 3 * 3) ] / 3 = [ 3 √6 ] / 3 = √6

  2. mckayla_04
    • 2 years ago
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    can you rationalize 3 over radical 2?

  3. Rohangrr
    • 2 years ago
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    radical 3 two's cancel ( as long as the last two is not under the radical)

  4. Kreshnik
    • 2 years ago
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    \[\Large \frac32 \sqrt2\] this is correct.

  5. satellite73
    • 2 years ago
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    \[\frac{\sqrt{18}}{\sqrt{3}}=\sqrt{\frac{18}{3}}=\sqrt{6}\]no need for rationalizng denominator

  6. satellite73
    • 2 years ago
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    \[\frac{3}{\sqrt{2}}=\frac{3}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}=\frac{3\sqrt{2}}{2}\]this one does require rationalizing denominator

  7. Kreshnik
    • 2 years ago
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    3 \cdot2 = \[3 \cdot 2\] on latex ;) @satellite73

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