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What are the questions here? I'm not sure I understand. Do you need to simplify? Rationalize?

yes simplify. im sorry

\[\frac{7}{10i}=\frac{7}{10i}\times \frac{i}{i}=\frac{7i}{-10}=-\frac{7i}{10}\]

#3, first of
\[\sqrt{49}=7\] and
\[(3+4i)-(2-5i)=1-i\]so start with
\[\frac{7}{1-i}\]

then
\[\frac{7}{1-i}=\frac{7}{1-i}\times \frac{1+i}{1+i}=\frac{7(1+i)}{2}\]

last line because
\[(a+bi)(a-bi)=a^2+b^2\]

then standard form looks like
\[\frac{7}{2}+\frac{7}{2}i\]

yeah, they were all wrong..

thanks for your effort though