Diyadiya
  • Diyadiya
Two candidates attempts to solve a quadratic equation of form \(x^2+px+q=0\) One starts with a wrong value of p and find the roots to be 2 and 6 the other starts with a wrong value of q and finds the roots to be 2, -9 the correct roots are :
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Just put in the roots into the quadratic equations, you will get 4 equations in two variables, solve them to get the value of correct p and q. And then solve the quadratic equation to get the right roots.
Diyadiya
  • Diyadiya
Ok i'll try that
anonymous
  • anonymous
By using the relation between roots and coefficient, -p=(2+6) p=-8 q=(2)(-9) = -18 x2-8x-18=0 solve this equation. (x+10)(x-2)=0 x=-10 or 2

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anonymous
  • anonymous
Oh Nice!
Diyadiya
  • Diyadiya
But they start with wrong value of p
Callisto
  • Callisto
I was thinking 'One starts with a wrong value of p and find the roots to be 2 and 6', that means q is correct, that is q =2x6 =12 ' the other starts with a wrong value of q and finds the roots to be 2, -9' that means p is correct -p = -9+2 p =7 just put the values into the equation and solve it.. Dunno if it is correct..
Diyadiya
  • Diyadiya
Yeah that's right :) @Callisto
Diyadiya
  • Diyadiya
-3 and -4 ?
Callisto
  • Callisto
That's what i've got.. :S
Diyadiya
  • Diyadiya
ok thats right :D Thanks everyone :)
angela210793
  • angela210793
I think Vieta's formulas would work in here
Diyadiya
  • Diyadiya
What's Vieta's formula ?
angela210793
  • angela210793
http://en.wikipedia.org/wiki/Vieta%27s_formulas

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