Two candidates attempts to solve a quadratic equation of form \(x^2+px+q=0\) One starts with a wrong value of p and find the roots to be 2 and 6 the other starts with a wrong value of q and finds the roots to be 2, -9 the correct roots are :
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Just put in the roots into the quadratic equations, you will get 4 equations in two variables, solve them to get the value of correct p and q. And then solve the quadratic equation to get the right roots.
Ok i'll try that
By using the relation between roots and coefficient,
solve this equation.
x=-10 or 2
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But they start with wrong value of p
I was thinking 'One starts with a wrong value of p and find the roots to be 2 and 6', that means q is correct, that is q =2x6 =12
' the other starts with a wrong value of q and finds the roots to be 2, -9' that means p is correct
-p = -9+2
just put the values into the equation and solve it..
Dunno if it is correct..