anonymous
  • anonymous
Solve the equation. Check both solutions and only write the real solution(s). v2x + 3 = x *v stands for sqrt A. {-1} B. {3} C. {-1, 3}
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
I think B.
eyust707
  • eyust707
i think so too! negitive square roots are not real.
anonymous
  • anonymous
I can't really tell what's going on the way you have the math written. Is it: \[\sqrt{2}x+3=x\] \[\sqrt{2x}+3=x\] or \[\sqrt{2x+3}=x\]

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eyust707
  • eyust707
thats a good point because 3 isnt actually a solution the way u wrote it
anonymous
  • anonymous
@TheFigure the last one you wrote is how it looks
anonymous
  • anonymous
Alright - this one. \[\sqrt{2x+3}=x\]
anonymous
  • anonymous
First, I'd square both sides to get the x out from under that square root:\[\sqrt{2x+3}^2=x^2\]Then, I'd recognize that it is quadratic and move everything to one side. \[0=x^2-2x+3\]From here, you can either use the quadratic formula or factor (depending on where you are in your math class).
anonymous
  • anonymous
Yikes - I blew it! Let's try that again... It should be:\[0=x^2-2x-3\]
anonymous
  • anonymous
Now it factors: \[0=x^2-2x-3\] \[0=(x-3)(x+1)\] x=-1, 3

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