anonymous
  • anonymous
Find the horizontal limit(s) of the following function: f(x) = \frac {11 x^3 - 9 x^2 -10 x }{ 9 - 11 x - 10 x^3 } ?and ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
(-11x^3+9x^2+10x)
anonymous
  • anonymous
how so i solve it?
Shayaan_Mustafa
  • Shayaan_Mustafa
kindly make standard form of your question. so I could understand.

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More answers

Shayaan_Mustafa
  • Shayaan_Mustafa
@rukh
anonymous
  • anonymous
Find the horizontal limit(s) of the following function: f(x) = \frac {11 x^3 - 9 x^2 -10 x }{ 9 - 11 x - 10 x^3 }
Shayaan_Mustafa
  • Shayaan_Mustafa
I told in fraction form correctly..
Shayaan_Mustafa
  • Shayaan_Mustafa
\[f(x)=(11x ^{3}-9x ^{2}-10x)/(9-11x-10x ^{3})\]is this your fraction looks like?
anonymous
  • anonymous
see attached
1 Attachment
anonymous
  • anonymous
yes
Shayaan_Mustafa
  • Shayaan_Mustafa
ok now.. as in your question. horizontal limits mean domain of the function. DOMAIN: it is where function is defined. for example if\[\lim_{x \rightarrow 0}1/x=\infty\] because anything divided by zero, goes to infinity. so the function is not defined at infinity. so every number except this is its domain. because at 0 1/x is not defined.
Shayaan_Mustafa
  • Shayaan_Mustafa
got it ?
anonymous
  • anonymous
sort of
anonymous
  • anonymous
but the answer will be a set then?
Shayaan_Mustafa
  • Shayaan_Mustafa
yes. it will be a set.
anonymous
  • anonymous
horizontal asymptote is the ratio of the leading coefficents, since the degree of the numerator and denominator are the same (they are both 3)
Shayaan_Mustafa
  • Shayaan_Mustafa
\[f(x)=(11x ^{3}-9x ^{2}-10x)/(9-11x-10^{3})\]In this function denominator must not be zero.
anonymous
  • anonymous
therefore your horizontal asymptote is \[y=-\frac{11}{10}\]
anonymous
  • anonymous
ok, my homework program does not accept a set as the answer, it says that the answers must be a number
anonymous
  • anonymous
and secondly - 11/10 is not being accepted either
anonymous
  • anonymous
then there is a mistake, but i can assure you that is what it is unless they want you to write \[y=-\frac{11}{10}\]
anonymous
  • anonymous
im supposed to get 2 answers for this problem
anonymous
  • anonymous
if -11/10 is one..whats the other?
Mertsj
  • Mertsj
Did you double check to see if the problem is posted correctly?
Mertsj
  • Mertsj
Or maybe they want it in decimal form.
anonymous
  • anonymous
yes its correct
Mertsj
  • Mertsj
What's correct?
Shayaan_Mustafa
  • Shayaan_Mustafa
it will define for all real numbers. X=all
anonymous
  • anonymous
the problem was posted correctly
anonymous
  • anonymous
i need 2 answers . if -11/ 10 is one, whats the other?
Mertsj
  • Mertsj
I don't know. Are they asking for the horizontal asymptotes? Because there is only one.
anonymous
  • anonymous
there is one, it is the ratio of the leading coefficients. there is no other
anonymous
  • anonymous
this is so complicated....:(
Mertsj
  • Mertsj
Maybe they want you to say as x approaches positive infinity, the limit is -11/10 and as x approaches negative infinity, the limit is -11/10
anonymous
  • anonymous
they are asking for horizonal limits...is this the same as horizontal asymptotes?
Mertsj
  • Mertsj
Satellite???
anonymous
  • anonymous
ok both answers are -11/10 and they did want it in decimal form. thanks guys
Mertsj
  • Mertsj
yw. I'll take the bows for Satellite's work.
Shayaan_Mustafa
  • Shayaan_Mustafa
as I have solved this equation vertical asymptote= NO horizontal asymptote= -11/10 oblique asymptote= NO
anonymous
  • anonymous
\[f(x) = \frac {11 x^3 - 9 x^2 -10 x }{ 9 - 11 x - 10 x^3 }\] is what is written, i cannot read the word document. numerator is a polynomial of degree 3 denominator is a polynomial of degree 3 (same degree) horizontal asymptote, limit as x goes to infinity, etc is \[y=-\frac{11}{10}=-1.1\] the ratio of the leading coefficeints. there is no other answer
anonymous
  • anonymous
thanks so much
Shayaan_Mustafa
  • Shayaan_Mustafa
you are ever welcome.

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