anonymous
  • anonymous
a circular coil of radius 5cm and resistance .2ohms is placed in a uniform magnetic field perpendicular to the plane of the coil. the magnitude of the field changes with time according to B=.50e^(-20t)T. what is the magnitude of the current induced in the coil at t=2s?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
This could help: http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/indcur.html I think that EMF must be calculated first. prior to this flux across coil area must be found. Then, current is easily obtained via Ohm's Law.
anonymous
  • anonymous
When I wrote flux, I mean derivative of flux relative to time \[d \phi/dt\]
anonymous
  • anonymous
First of all, find flux using following formula: phi(flux)=B*A.....where B is magnetic field and A is area . using lenz's law: Einduced=-d(phi)/dt find the value of Einduced at t=2. And using ohm's law: I=Einduced/R....Where R is Resistance ...

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
i'm not getting the right answer =/... \[emf=d \phi/dt=A*dB/dt\] \[dB/dt=-20*.5e ^{-20t}\]...right? and @ t=2s and A being pi(.05)^2... emf=-3.3*10^-19... I=emf/R=-1.67*10^-18. not even close to any answers
ujjwal
  • ujjwal
i get an answer which is equal to 1.07*10^-18.. is angular velocity= 20 rotations per sec ??
anonymous
  • anonymous
i didn't use angular velocity
ujjwal
  • ujjwal
I guess you sholuld use angular velocity too

Looking for something else?

Not the answer you are looking for? Search for more explanations.