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elica85
Group Title
a circular coil of radius 5cm and resistance .2ohms is placed in a uniform magnetic field perpendicular to the plane of the coil. the magnitude of the field changes with time according to B=.50e^(20t)T. what is the magnitude of the current induced in the coil at t=2s?
 2 years ago
 2 years ago
elica85 Group Title
a circular coil of radius 5cm and resistance .2ohms is placed in a uniform magnetic field perpendicular to the plane of the coil. the magnitude of the field changes with time according to B=.50e^(20t)T. what is the magnitude of the current induced in the coil at t=2s?
 2 years ago
 2 years ago

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juancarlosquintero_EC Group TitleBest ResponseYou've already chosen the best response.0
This could help: http://hyperphysics.phyastr.gsu.edu/hbase/magnetic/indcur.html I think that EMF must be calculated first. prior to this flux across coil area must be found. Then, current is easily obtained via Ohm's Law.
 2 years ago

juancarlosquintero_EC Group TitleBest ResponseYou've already chosen the best response.0
When I wrote flux, I mean derivative of flux relative to time \[d \phi/dt\]
 2 years ago

Taufique Group TitleBest ResponseYou've already chosen the best response.1
First of all, find flux using following formula: phi(flux)=B*A.....where B is magnetic field and A is area . using lenz's law: Einduced=d(phi)/dt find the value of Einduced at t=2. And using ohm's law: I=Einduced/R....Where R is Resistance ...
 2 years ago

elica85 Group TitleBest ResponseYou've already chosen the best response.0
i'm not getting the right answer =/... \[emf=d \phi/dt=A*dB/dt\] \[dB/dt=20*.5e ^{20t}\]...right? and @ t=2s and A being pi(.05)^2... emf=3.3*10^19... I=emf/R=1.67*10^18. not even close to any answers
 2 years ago

ujjwal Group TitleBest ResponseYou've already chosen the best response.0
i get an answer which is equal to 1.07*10^18.. is angular velocity= 20 rotations per sec ??
 2 years ago

elica85 Group TitleBest ResponseYou've already chosen the best response.0
i didn't use angular velocity
 2 years ago

ujjwal Group TitleBest ResponseYou've already chosen the best response.0
I guess you sholuld use angular velocity too
 2 years ago
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