anonymous
  • anonymous
a motorist travelling with a constant speed of 15 m/s passes a school zone sign where the speed limit is 10 m/s. Just as the motorist passes, a police officer on a motorcycle starts off at the same school zone sign in pursuit with constant acceleration of 20 m/s^2.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Well I assume you are asking when he catches the motorist Lets start off by taking the board sign as the origin Now lets say they meet after time t Dist.travelled by motorist in time t=10t By policeman=\[20(t^2)\] Now equate them because that is where they meet You get two answers t=0 and t=2
anonymous
  • anonymous
ah no thats wrong
anonymous
  • anonymous
Go on explain why

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anonymous
  • anonymous
t=0.75s v=v0+at
anonymous
  • anonymous
What?
anonymous
  • anonymous
velocity = initial velocity + acceleration*time
anonymous
  • anonymous
So what the motorist didn't have any acceleration.And I equated the distance travelled by both now the velocities
anonymous
  • anonymous
his is constant
anonymous
  • anonymous
Yeah so what's you point
anonymous
  • anonymous
lol oops forgot to post this part LOL (a)How much time elapses before the officer catches up with the motorcycle? (b)What is the total distance that each have travelled at that point?
anonymous
  • anonymous
Well he catches after 2 seconds at a distance 20 m later
anonymous
  • anonymous
just checking answer...i forgot to post a bit of the question (a)How much time elapses before the officer catches up with the motorcycle? (b)What is the total distance that each have travelled at that point?
anonymous
  • anonymous
5.65m?
anonymous
  • anonymous
sorry 5.625
anonymous
  • anonymous
and 0.75s
anonymous
  • anonymous
after t seconds the motorist goes 15t meters, i believe the formula for distance is d=v_ot+1/2at^2
anonymous
  • anonymous
But the policeman's initial velocity was 0
anonymous
  • anonymous
Oh I forgot and kept initial velocity for biker as 10 instead of 15
anonymous
  • anonymous
Anyway just change the numbers
anonymous
  • anonymous
yes, so 15t=1/2*20t^2
anonymous
  • anonymous
Yeah that'd give you the answer
anonymous
  • anonymous
but t=.75s? and so answer is 5.625?
anonymous
  • anonymous
t=1.5s
anonymous
  • anonymous
total distance travelled is 15(1.5)=22.5m
anonymous
  • anonymous
ohhh so you use a quadratic to find t in d=v_ot+1/2at^2
anonymous
  • anonymous
i was using v=vo+at
anonymous
  • anonymous
so if there is distance involved you have to use that formula...
anonymous
  • anonymous
first you have to equate 15t with v_ot+1/2at^2, solve for t, then solve for d
anonymous
  • anonymous
distance traveled by motorist in t seconds is 15t, distance travelled by cop in t seconds is 10t^2,
anonymous
  • anonymous
haha thanks

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