Determine an expression for the cost

- anonymous

Determine an expression for the cost

- schrodinger

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- anonymous

Pi = MC squared + the radius of pathagorean theorum divided by the square root of exponent X

- anonymous

lol

- anonymous

i don't either.

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## More answers

- anonymous

its correct assuming you buy more than 100 chips, otherwise, no

- anonymous

you can define the cost function with the restricted domains

- anonymous

yes, use a piece-wise function

- anonymous

a piece-wise function

- anonymous

also you should usee p instead of n, as the question asked for that

- anonymous

yes

- anonymous

you'll need to give C no matter what amount is purchased though...

- anonymous

p>=100

- anonymous

\[[100, \infty)\]

- anonymous

for 0<=p<100
C(P)=200

- anonymous

C(P)=2p rather lol

- anonymous

its a piece-wise function and is linear

- anonymous

yw

- anonymous

I'm wondering if they also want it for under 100. Then you'd have two piecewise functions.
c(n)=2n,
nâ‰¤100
c(n) = 200+1.75(n-100) when n>100

- anonymous

But the first part... would they want that as well?

- anonymous

Oh I see.

- anonymous

Sorry, I didn't read through all the comments...

- anonymous

It's just a line. First, get it in slope-intercept form.
c(n) = 200+1.75(n-100)
= 200 +1.75n - 175
c(n)=1.75n +25
Your y-intercept is 25. Your slope is 1.75.

- anonymous

Looks good.

- anonymous

just in case, because the problem did not state that they'll aways buy more than 100 chips, the function should look like this:|dw:1333233617956:dw|

- anonymous

@dpaInc That's what I was thinking too. It's better safe than sorry if they don't specify "over 100 chips"

- anonymous

Should be integers I think.

- anonymous

since you can't have half of a chip :-)

- anonymous

for the piece-wise function theres an implied domain of [0, infinity) because you wouldn't purchase negative chips

- anonymous

but you could purchase 0, and as brinethery said, you'd want to restrict it to integers

- anonymous

you could just say all whole numbers

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