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Pi = MC squared + the radius of pathagorean theorum divided by the square root of exponent X
i don't either.
its correct assuming you buy more than 100 chips, otherwise, no
you can define the cost function with the restricted domains
yes, use a piece-wise function
a piece-wise function
also you should usee p instead of n, as the question asked for that
you'll need to give C no matter what amount is purchased though...
for 0<=p<100 C(P)=200
C(P)=2p rather lol
its a piece-wise function and is linear
I'm wondering if they also want it for under 100. Then you'd have two piecewise functions. c(n)=2n, n≤100 c(n) = 200+1.75(n-100) when n>100
But the first part... would they want that as well?
Oh I see.
Sorry, I didn't read through all the comments...
It's just a line. First, get it in slope-intercept form. c(n) = 200+1.75(n-100) = 200 +1.75n - 175 c(n)=1.75n +25 Your y-intercept is 25. Your slope is 1.75.
just in case, because the problem did not state that they'll aways buy more than 100 chips, the function should look like this:|dw:1333233617956:dw|
@dpaInc That's what I was thinking too. It's better safe than sorry if they don't specify "over 100 chips"
Should be integers I think.
since you can't have half of a chip :-)
for the piece-wise function theres an implied domain of [0, infinity) because you wouldn't purchase negative chips
but you could purchase 0, and as brinethery said, you'd want to restrict it to integers
you could just say all whole numbers